lectron moves at a velocity of 2.20 x 10^6 m/s in a direction perpendicular to a magnetic field of strength 1.89 T. How much force will the electron experience?

A proton is accelerated from east to west in a particle accelerator to 2.77x10^6 m/s and then passes through a uniform magnetic field of magnitude 39.5 T that is directed from south to north. What magnitude force will act on the proton as it passes through the field? Give your answer in pN (1 picoNewton = 1.0 x 10^-12 N).

A magnesium-24 ion has a positive charge that is double the charge of a proton, and a mass of 3.98 ✕ 10−26 kg. At a particular instant, it is moving with a speed of 4.90 ✕ 106 m/s through a magnetic field. At this instant, its velocity makes an angle of 65° with the direction of the magnetic field at the ion's location. The magnitude of the field is 0.200 T. (a)What is the magnitude of the magnetic force (in N) on the ion? N (b)What is the magnitude of the ion's acceleration (in m/s2) at this instant? m/s2

A particle with a charge of q = - 1.24 × 10-8 ℃ is moving with instantaneous velocity V = 1.42 x 104 m/si +3.85 x 104 m/sĵ. What is the force exerted on this particle by a magnetic field: a) B = 11.4 TÎ and b) B = 11.4Tk?