An electrochemical cell has the following cell reaction: Which is the half-reaction occurring at the anode? 021(aq) → 12(s) + 2 c O PbO₂(s) 4 H*(aq) +2ePb2(aq) + 2 H₂O(l) O Pb²(aq) + 2 H₂O()→PbO₂(s) +4 H*(aq) + 2 e Ⓒ12(3)+221 (09) PbO₂(s) + 21 (aq) → Pb² (aq) + 1₂(s)

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Chapter1: Chemical Foundations
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An electrochemical cell has the following cell reaction:
Which is the half-reaction occurring at the anode?
O21 (aq) → 12(s) + 2 c
OPbO2(s) 4 H*(aq) +2ePb2(aq) + 2 H₂O(l)
O Pb2 (aq) + 2 H₂O) PbO₂(s)+4 H(aq) + 2 e
Ⓒ12(3)+2
2 1 (og)
PbO₂(s) + 21 (aq) → Pb² (aq) + 12(s)
Transcribed Image Text:An electrochemical cell has the following cell reaction: Which is the half-reaction occurring at the anode? O21 (aq) → 12(s) + 2 c OPbO2(s) 4 H*(aq) +2ePb2(aq) + 2 H₂O(l) O Pb2 (aq) + 2 H₂O) PbO₂(s)+4 H(aq) + 2 e Ⓒ12(3)+2 2 1 (og) PbO₂(s) + 21 (aq) → Pb² (aq) + 12(s)
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