Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder). One way to represent this equilibrium is: 2 Al(s) +3 Br2(1) 2 AIBR3(s) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above. 1) Al(s) + 3/2 Br2) AIBr3(s) K, %3D 2) 2 AIBr3(s) =2 Al(s) + 3 Br2(1) K, = 3) AIB33(s) e Al(s) + 3/2 Br2(1) K3 =

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Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white
powder).
One way to represent this equilibrium is:
2 Al(s) +3 Br2()=2 AIBR3(s)
We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are
related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above.
1) Al(s) + 3/2 Br21)= AIB33(s)
K, =
2) 2 AIB13(s)
=2 Al(s) + 3 Br2(1)
K, =
3) AIBR3(s)
Al(s) + 3/2 Br2(1) K3=
Visited
rop your selection from the following list to complete the answer:
1/K
K2
(1/K) /2
Transcribed Image Text:Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder). One way to represent this equilibrium is: 2 Al(s) +3 Br2()=2 AIBR3(s) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above. 1) Al(s) + 3/2 Br21)= AIB33(s) K, = 2) 2 AIB13(s) =2 Al(s) + 3 Br2(1) K, = 3) AIBR3(s) Al(s) + 3/2 Br2(1) K3= Visited rop your selection from the following list to complete the answer: 1/K K2 (1/K) /2
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