Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder). One way to represent this equilibrium is: 2 Al(s) +3 Br2(1) 2 AIBR3(s) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above. 1) Al(s) + 3/2 Br2) AIBr3(s) K, %3D 2) 2 AIBr3(s) =2 Al(s) + 3 Br2(1) K, = 3) AIB33(s) e Al(s) + 3/2 Br2(1) K3 =

Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder). One way to represent this equilibrium is: 2 Al(s) +3 Br2(1) 2 AIBR3(s) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above. 1) Al(s) + 3/2 Br2) AIBr3(s) K, %3D 2) 2 AIBr3(s) =2 Al(s) + 3 Br2(1) K, = 3) AIB33(s) e Al(s) + 3/2 Br2(1) K3 =

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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