Albinism (lack of skin pigmentation) is caused by an autosomal recessive allele. A man and woman, both normally pigmented, have an albino child together. For this trait, what is the genotype of both parents? Options Below: homozygous recessive homozygous dominant heterozygous hemizygous
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Albinism (lack of skin pigmentation) is caused by an autosomal recessive allele. A man and woman, both normally pigmented, have an albino child together. For this trait, what is the genotype of both parents?
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- Albinism is an autosomal recessive condition characterized by absence of melanin pigment from the skin, eye and hair. Two carriers of albinism marry and plan to have FIVE children. Assume a 1:1 sex ratio. What is the probability that at least 3 children will be normal?Please define the following terms: Gene Allele Dominant Recessive Homozygous HeterozygousAlbinism is an autosomal (not sex-linked) recessive trait. A man and woman are both of normal pigmentation and have one child out of three who is albino (without melanin pigmentation). What are the genotypes of the albino's parents? One parent must be homozygous for the recessive allele; the other parent can be homozygous dominant, homozygous recessive, or heterozygous. Both parents must be homozygous dominant. One parent must be heterozygous; the other parent can be homozygous dominant, homozygous recessive, or heterozygous. Both parents must be heterozygous. One parent must be homozygous dominant; the other parent must be heterozygous. O000
- Achondroplasia, is characterized by difficulty converting cartilage to bone and thus results in shortened limbs. This trait is autosomal dominant. (A = achondroplasia allele; a = average height allele.) A husband and wife both have achondroplasia. The couple have a total 12 living children: 6 boys and 6 girls. The husband is colorblind, which is an X-linked recessive trait, and the wife believes there is a chance she is a carrier of colorblindness, since that trait runs in her family. One of the couple’s daughters and three of their sons are colorblind. (Xc = colorblindness allele; XC = normal color vision allele.) A. Is the mother a carrier of the colorblindness allele? Please explain the meaning of the term "carrier", and answer this question, based upon all of the information provided.Achondroplasia,is characterized by difficulty converting cartilage to bone and thus results in shortened limbs. This trait is autosomal dominant. (A = achondroplasia allele; a = average height allele.) A husband and wife both have achondroplasia. The couple have a total 12 living children: 6 boys and 6 girls. The husband is colorblind, which is an X-linked recessive trait, and the wife believes there is a chance she is a carrier of colorblindness, since that trait runs in her family. One of the couple’s daughters and three of their sons are colorblind. (Xc = colorblindness allele; XC = normal color vision allele.) a) Please list all of the different gametes that the husband can produce. b) Please list all of the different gametes that the wife can produce.Tightly curled hair is caused by a dominant autosomal gene in humans. If a heterozygous curly-haired person marries a person with straight hair, what phenotypes (and in what proportions) are expected in the offspring? O 1 curly: 1 straight 1 curly: 2 straight O 1 curly: 3 straight O 2 curly: 1 straight O 3 curly: 1 straight Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining "
- Sickle cell anemia is inherited as an autosomal recessive condition. It also exhibits incomplete dominance in that the heterozygous genotype displays a mild form of the disease known as sickle cell trait while individuals with the homozygous recessive genotype have a severe form of SCA. A man who has severe sickle cell anemia marries a woman who suffers from a mild trait. What is the probabilitu they will have a child with severe SCA?What is the probability they will have a child with mild SCA? What is the probability they will have a normal child? Show ALL work using punnett squares.Both have a genetic disorder, but they already have one child who does not have the disorder. They would like to have more children and were told by a friend that since their first child was normal their future children would be normal as well. Explain to them the probability of future offspring being normal or having the disease (assume that this is an autosomal disease). Be sure to tell them whether the disease is brought about by a dominant or recessive allele and what fraction of their children (if any) could be carriers for the disease.Huntington’s disease, a neurodegenerative genetic disorder that typically becomes noticeable in middle age, is due to an autosomal dominant allele. Sickle cell anemia, on the other hand, is a genetic blood disorder due to a recessive allele. Mary is a carrier of the allele for sickle cell anemia but has no sign of any neurodegenerative disorder in her family. She married Paul whose father died of Huntington’s disease. His mother, however, is not inflicted with that condition. Neither of his parents exhibits sickle cell anemia. What are the genotypes of Jane and Paul? If they plan to have four children, what is the probability that: all their children will be normal? _________________________________ they will have a son with Huntington’s disease? _________________________ they will have a daughter inflicted with both conditions?________________
- Cystic Fibrosis is an autosomal recessive disorder. A couple are both carriers of the recessive allele (both heterozygous (Cc)) and have the normal wild-type phenotype. What is the probability of the following occurring; If they have one child, what is the probability of it having cystic fibrosis (cc)?Albinism is an autosomal (not sex-linked) recessive trait. A man and woman are both of normal pigmentation and have one child out of three who is albino (without melanin pigmentation). What are the genotypes of the albino's parents? Both parents must be homozygous dominant. Both parents must be heterozygous. One parent must be homozygous dominant; the other parent must be heterozygous. One parent must be heterozygous; the other parent can be homozygous dominant, homozygous recessive, or heterozygous. One parent must be homozygous for the recessive allele; the other parent can be homozygous dominant, homozygous recessive, or heterozygous. O O O O OHemophilia is an X-linked recessive disorder and blood type is autosomal. If two healthy parents, one of which is blood type A and the other blood type B, produce a son who has hemophilia and is type O, what is the probability that their next child will be a son with hemophilia and blood type B? 1/2 3/16 1/4 1/8 1/16