College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Albert Einstein is pondering how to write his (soonto-be-famous) equation. He knows that energy E is a function of mass m and the
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- Given: R(N)=f(N)g(N) where f(N) = 7.2N and g(N) = (1 - 7.9/N. If R(N) = H means that R'(N) = 0 and H = 10.5N, what is the value of N that causes R'(N) = 0?arrow_forwardA particle has γ=18,399. a)Calculate c-v in m/s. (I would have asked for 1 - v/c, making the answer dimensionless, but the system doesn't seem to take numbers that small. Gamma is chosen to make the particle extremely close to the speed of light.) If your calculator gives problems, you might want to solve the appropriate equation for c-v or c(1 - v/c) and use an approximation. b) In the previous problem, in a race to the moon, by 3/4ths the distance, light is one or ten meters ahead of the particle. We routinely approximate mass as zero, gamma as infinite, and speed as the speed of light. ("Massless particles" -- gamma and m have to be eliminated from the expressions. Light is a true massless particle.) If a massless particle has momentum 1,739 MeV/c, calculate its energy in MeV.arrow_forwarddx 4x 3. In so-called "natural units" (which is just a sneaky way to let us ignore a bunch of constants), the relativistic kinetic energy of a rigid body is given by the formula 1 КЕ — т V1 – v2 where m is the rest mass of the body and v is its relative speed. Alien scientists on a space station are observing an object falling into a black hole. As the object falls, it is disintegrating, losing mass at a rate of 3 (so its mass is changing at a rate of -3). How fast is the kinetic energy of the main part of the object changing when its mass is 20, its velocity is .7, and it is accelerating at a rate of .1 (remember that acceleration is the derivative of velocity with respect to time: a = dt 1Note that this formula does not make sense when v > 1. That is because in natural units, a speed of 1 corresponds to the speed of light, and nothing with positive rest mass can go that fast.arrow_forward
- To study Brownian motion, Bob, a student at the University of Ottawa, used his camera to capture the positions (i.e. displacements) of 50 microscopic dust particles floating on the surface of the water of his aquarium. By setting his camera to record 10 frames per second and noting down each particle's 2D displacement for each recorded frame, he managed to obtain the following mean-displacement vs time graph: 1600 1400 1200 2 1000 V 800 600 400 200 20 40 60 80 100 120 140 Time (s) a. Use the above mean-displacement graph to roughly approximate the diffusion coefficient D of the dust particles with units of um? /s. b. From the diffusion coefficient estimate in a), calculate the root mean- square displacement expected between each consecutive frame? c. Are the diffusion coefficient D and mean-square displacement calculated reasonable for a microscopic particle, or did Bob make a mistake in his calculations? Mean-square disp. (cm²)arrow_forwardPlease please please answer everything as fast as possible please NOTE: This is not a graded question, this is not a graded questionarrow_forwardWhen measuring with a muline, it was measured as n=10 when the speed was 1.1 m/s, and as n=32 when the speed was 1.5 m/s. What is the velocity formula?arrow_forward
- been having some trouble with this problem: Michelson used rotating mirrors, similar to those shown below, to calculate the speed of light. Light is emitted from the light source, reflects from mirror surface X to the plane mirror, and then to the position of surface Z. By the time the light moves from the X to Z position, mirror surface X will have moved to the position of mirror surface Z. The light then continues to the observer. The distances from the light source and the observer to the rotating mirrors are negligible. The distance from the rotating mirrors to the plane mirror is 35.0 km.If the mirrors are rotating at 480 rev/s, the speed of light calculated from the given information isarrow_forwardA galaxy G is moving away radially with speed with respect to an observer O. The relation between X, the wavelength of light emitted at G, and λo, the wavelength observed at O, is 入。 λ = λe λε 1+B 1- B' = where ẞ v/c (c is the speed of light). For ẞ < 1 find a power series expansion of the above formula up to and including terms of order ẞ³.arrow_forward1. Consider two time interval measurements: t1 = 0.84±0.8 sec and t2 = 0.96 ± 0.8 sec. Considering their uncertainties, can you conclude that the two measurements are the same? Explain.arrow_forward
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