A particle has γ=15,687.  Calculate c-v in m/s.  (I would have asked for 1 - v/c, making the answer dimensionless, but the system doesn't seem to take numbers that small.  Gamma is chosen to make the particle extremely close to the speed of light.) If your calculator gives problems, you might want to solve the appropriate equation for c-v or c(1 - v/c) and use an approximation.

In this problem we will observe how the momentum of an electron changes as its velocity approaches the speed of light. The mass of an electron is 9.109 × 10-31 kg.   Part (a)  First, what is the momentum of an electron which is moving at the speed of a car on a highway, say 29 m/s, in kilogram meters per second?

What are the two postulates of special relativity? (Choose two answers.) A In any closed system, the total momentum will not change. B F=ma (c) The entropy of an isolated system will always increase over time. The speed of light is the same regardless of the speed of the observer or the speed of the source. Light travels to us from the hands of the clock. If we could move away from the clock at the speed of light, time will appear to stand still. If you measure both the position of a particle and its momentum, then the product of the F uncertainties of these two measurements must always be at least half of the reduced Planck's constant. For all possible paths between two points, the actual trajectory is the one that results in the action being minimized.

A particle has γ=18,399. a)Calculate c-v in m/s. (I would have asked for 1 - v/c, making the answer dimensionless, but the system doesn't seem to take numbers that small. Gamma is chosen to make the particle extremely close to the speed of light.) If your calculator gives problems, you might want to solve the appropriate equation for c-v or c(1 - v/c) and use an approximation. b) In the previous problem, in a race to the moon, by 3/4ths the distance, light is one or ten meters ahead of the particle. We routinely approximate mass as zero, gamma as infinite, and speed as the speed of light. ("Massless particles" -- gamma and m have to be eliminated from the expressions. Light is a true massless particle.) If a massless particle has momentum 1,739 MeV/c, calculate its energy in MeV.

Uranium-238 decays via the alpha decay process.  Part (a)  Calculate the energy released in units of megaelectron volts when a uranium-238 nucleus undergoes alpha decay.  Part (b)  What fraction of the mass of a single uranium-238 nucleus is destroyed in the decay?  Part (c)  Why is difficult to observe the change in mass for a macroscopic sample of uranium-238?

Question 1 Make the conversion of 2.4 Km/h2 to m/s2. O 6.67 E(-4) 1.85 E(-4) 1.85 E(-7) 0.67 1.5 Question 2 In solving a physics problem you end up with m in the numerator and m/s in the denom units for your answer are O m/s O m^2/s O m O 1/s Question 3

A 6.00kg ornament is held at rest by two light wire that forms 30 degree angles with the vertical. an external force of magnitude F acts vertically downwards on the ornament. the tension exerted by each of the two wires is denoted by T. if the magnitude of the force F is 410N what is teh magnitude of the Tension T

I1:00:00 PM Problem 3: Suppose the speed of light were only 3000.0 m's. A jet fighter moving toward a target on the ground at 810 m/s shoots bullets, each having a muzzle velocity of 1050 m's. Randomized Variables v-810 m/s v2 1050 m's ed What is the velocity of the bullets relative to the target in km's? Grade Sommary Deductions 0% Potential 100%

Given u = −7i − 5j and v = −10i − 9j, what is projvu?  a −9.937i − 8.943j  b −6.956i − 4.968j  c −6.354i − 5.718j  d −4.448i − 3.177j

Imagine you derive the following expression by analyzing the physics of a particular system: v2=v20+2axv2=v02+2ax. The problem requires solving for xx, and the known values for the system are a=2.55meter/second2a=2.55meter/second2, v0=21.8meter/secondv0=21.8meter/second, and v=0meter/secondv=0meter/second. Perform the next step in the analysis.