Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN: 9780134463216
Author: Robert F. Blitzer
Publisher: PEARSON
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**Factoring Polynomials**

**Problem:**

Factor the polynomial given below:

\[
\frac{1}{7}x^3 - \frac{4}{35}x^2
\]

In the expression above, you need to identify any common factors and factor them out.

**Solution:**

1. **Identify the Greatest Common Factor (GCF):**
   - The coefficients are \(\frac{1}{7}\) and \(\frac{4}{35}\).
   - The common factor for \(\frac{1}{7}\) and \(\frac{4}{35}\) is \(\frac{1}{35}\).
   - The common factor for the variable terms \(x^3\) and \(x^2\) is \(x^2\).

2. **Factor Out the GCF:**
   - The GCF of the overall expression is \(\frac{1}{35}x^2\).
   - Factoring this out gives:
   \[
   \frac{1}{35}x^2 \left( 5x - 4 \right)
   \]

3. **Type Your Answer:**

In factored form, the polynomial is:
\[
\frac{1}{35}x^2 (5x - 4)
\]

Remember to simplify every term and check your work by multiplying the factors back together to ensure you get the original expression.
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Transcribed Image Text:**Factoring Polynomials** **Problem:** Factor the polynomial given below: \[ \frac{1}{7}x^3 - \frac{4}{35}x^2 \] In the expression above, you need to identify any common factors and factor them out. **Solution:** 1. **Identify the Greatest Common Factor (GCF):** - The coefficients are \(\frac{1}{7}\) and \(\frac{4}{35}\). - The common factor for \(\frac{1}{7}\) and \(\frac{4}{35}\) is \(\frac{1}{35}\). - The common factor for the variable terms \(x^3\) and \(x^2\) is \(x^2\). 2. **Factor Out the GCF:** - The GCF of the overall expression is \(\frac{1}{35}x^2\). - Factoring this out gives: \[ \frac{1}{35}x^2 \left( 5x - 4 \right) \] 3. **Type Your Answer:** In factored form, the polynomial is: \[ \frac{1}{35}x^2 (5x - 4) \] Remember to simplify every term and check your work by multiplying the factors back together to ensure you get the original expression.
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