2. Which of the following shows the correct vector representation of the tension in the web sling?A. T <-0.426,-0.640, 0.640>B. T <0.426, 0.640, -0.640>C. T <-0.640, 0.640, 0.426>D. T <1, 1.5, -1.5>A÷ X3. What is the magnitude of the equivalent concentrated load representing the weight of the box?18.00 N4. Which of the following is the CORRECT summation of moments about the x-axis?HINT: Use "force multiplied by perpendicular distance"A. Wbox(0.15) + Wwood (0.75) - Ty(1.5) = 0B. Wbox(0.15) - Wwood (0.75) + Ty(1.5) = 0C. Wbox(0.15) + Wwood (0.75) - Ty(1.5) + Tx(1.5) = 0D. Wbox(0.15) + Wwood (0.75) - Ty(1.5) - T₂(1.5) = 0B X5. What is the magnitude of the tension in Spiderman's web sling? After MJ completely forgot about Spiderman's identity, Peter decided to store all of the pictures and gifts MJ had given him in a box lyingon one corner of a 7 kg wooden platform supported by a hinge at K, located at the midpoint of HI. Spiderman also attached a web slingat G to hold the platform in equilibrium. The weights of the misarranged objects inside the box are idealized to have a triangulardistribution ALONG THE CENTER OF THE BOX as shown.y0.3mGN2mH1m1.5m0.45m80N/m1.5mX

Position vector of G: 0i + 0j + 1.5k Position vector of L: 1i + 1.5j + 0k Vector along sling:…

After MJ completely forgot about Spiderman's identity, Peter decided to store all of the pictures and gifts MJ had given him in a box lying on one corner of a 7 kg wooden platform supported by a hinge at K, located at the midpoint of HI. Spiderman also attached a web sling at G to hold the platform in equilibrium. The weights of the misarranged objects inside the box are idealized to have a triangular distribution ALONG THE CENTER OF THE BOX as shown.

After MJ completely forgot about Spiderman's identity, Peter decided to store all of the pictures and gifts MJ had given him in a box lying on one corner of a 7 kg wooden platform supported by a hinge at K, located at the midpoint of HI. Spiderman also attached a web sling at G to hold the platform in equilibrium. The weights of the misarranged objects inside the box are idealized to have a triangular distribution ALONG THE CENTER OF THE BOX as shown.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.

Question

2. Which of the following shows the correct vector representation of the tension in the web sling?
A. T <-0.426,-0.640, 0.640>
B. T <0.426, 0.640, -0.640>
C. T <-0.640, 0.640, 0.426>
D. T <1, 1.5, -1.5>
A÷ X
3. What is the magnitude of the equivalent concentrated load representing the weight of the box?
18.00 N
4. Which of the following is the CORRECT summation of moments about the x-axis?
HINT: Use "force multiplied by perpendicular distance"
A. Wbox(0.15) + Wwood (0.75) - Ty(1.5) = 0
B. Wbox(0.15) - Wwood (0.75) + Ty(1.5) = 0
C. Wbox(0.15) + Wwood (0.75) - Ty(1.5) + Tx(1.5) = 0
D. Wbox(0.15) + Wwood (0.75) - Ty(1.5) - T₂(1.5) = 0
B X
5. What is the magnitude of the tension in Spiderman's web sling?

After MJ completely forgot about Spiderman's identity, Peter decided to store all of the pictures and gifts MJ had given him in a box lying
on one corner of a 7 kg wooden platform supported by a hinge at K, located at the midpoint of HI. Spiderman also attached a web sling
at G to hold the platform in equilibrium. The weights of the misarranged objects inside the box are idealized to have a triangular
distribution ALONG THE CENTER OF THE BOX as shown.
y
0.3m
G
N
2m
H
1m
1.5m
0.45m
80N/m
1.5m
X

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