According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the percent of California residents who reported insufficient rest or sleep during each of the preceding 30 days is 7.6%, while this percent is 9% for Oregon residents. These data are based on simple random samples of 11848 California and 4571 Oregon residents. Calculate a 95% confidence interval for the difference between the proportions of Californians and Oregonians who are sleep deprived. Round your answers to 4 decimal places. Make sure you are using California as Group A and Oregon as Group B.

Q: In a survey, 10 people were asked how much they spent on their child's last birthday gift. The…

A: We have given that,  Sample mean (x̄) = 34, standard deviation (s)=6 and sample size (n) = 10 Then,…

Q: Listed below are the blood pressure measurements taken from the right and left arm of 5 patients.…

A: From the provided information, The mean and standard deviation of the right arm data can be obtained…

Q: In a survey, 12 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: From a simple random sample of 400 of the 1,395 colleges in our population, it was found that…

A: Given : 1395 colleges in our population  Population Size (N) = 1395 400 colleges selected randomly…

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: It is given that Sample size n = 250 Number of students receiving scholarship, X = 70 The critical…

Q: alculate a 95% confidence interval for the difference between the proportions of Californians and…

A: Let p1 and p2 be the two population proportions for California and Oregonians who are…

Q: If n = 220,p = 0.4,then what will be the 87.4% confidence interval for the population proportion?

A:

Q: Students at Green River plans a study to stats Test scores. Previous research has shown the…

A: We have given that  Margin of error =E =0.5 Population Standard deviation = 1 99%confidence…

Q: find the margin of error for a sample mean, given n=16, s=4, Xbar=17. for a 95% confidence interval.

A: The margin of error for sample mean is given by,

Q: A sample of 47 Charleston County households have a mean income of $32,346 with a standard deviation…

A: The sample size is 47, sample mean is $32346, and sample standard deviation is $8571. The confidence…

Q: According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the…

A: Reviewing information, Group A p1=7.8%=0.078 n1=11506 Group B p2=9.1%=0.091 n2=4792

Q: A June 2009 Harris Interactive poll asked people their opinions about the influence of advertising…

A: The value of z at 98% confidnce level is 2.326, which can be obtained by using the standard normal…

Q: In a survey, 13 people were asked how much they spent on their child's last birthday gift. The…

A: We have to construct ci.

Q: Cameron and Bailey each take random samples and construct 90% confidence intervals for the…

A:

Q: If n = 370 and p=0.31p, construct a 90% confidence interval. This should be rounded to three decimal…

A:

Q: If n=41n=41, ¯xx¯=36, and s=9s=9, find the margin of error for a 80% confidence level.

A: Answer - Given, Sample size n = 41,    x  = 36    and s = 9               80% confidence interval…

Q: In a survey, 32 people were asked how much they spent on their child's last birthday gift. The…

A: Given  sample size n=32 mean x¯=$33 standard deviation s=$12 confidence level =80%,…

Q: The Bureau of Alcohol, Tobacco, and Firearms (BATF) has been concerned about lead levels in…

A: Given, Range = 49 to 720 Margin of Error E = 10 at 90% confidence level  α = 0.1Critical value Zα2 =…

Q: one with a 95% confidence level and the other with a 99.7% confidence level. Which interval is…

A: Confidence interval is probability, which refers that population parameter will fall within set of…

Q: For a random sample of 48  professional soccer games, the variance of total points was 7.3 points.…

A: Sample size, Sample variance,  points. Confidence level,

Q: In a survey, 23 people were asked how much they spent on their child's last birthday gift. The…

A: Using excel formula “=T.INV(1-(0.2/2),22)”, the critical value of 80% confidence level is 1.321.

Q: In a survey, 24 people were asked how much they spent on their child's last birthday gift. The…

A: From the available information, Sample size, n =24 Sample mean, x = 31 Sample standard deviation, s…

Q: igh school soccer league there are a total of 256 players.

A: Given that Total players in high school soccer league (n) = 256 players The mean height of the…

Q: It is believed that slightly over 50% of Americans own pets. A 95% confidence interval for the…

A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…

Q: In a survey, 23 people were asked how much they spent on their child's last birthday gift. The…

A: Sample mean = x̅ = 46 Sample size = n = 23 Sample S.D = s = 12 Standard Error = s/√n  = 12/√23…

Q: ording to a report on sleep deprivation by the Centers for Disease Control and Prevention, the…

A: sample proportion 1 = 7.6% N1 = 11738 sample proportion 2 = 9.1% N2 = 4942

Q: According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the…

A: From the provided information,

Q: An article presents a study of the failure pressures of roof panels. Following are the failure…

A:

Q: A sample of 1,000 employees in an international company was taken to estimate the average…

A: Confidence interval of mean is given by, (X bar + - Z* sigma/√n) Where X bar is mean and sigma is…

Q: You are going to construct a 99% confidence interval for the proportion of hip replacement…

A:

Q: In a survey, 14 people were asked how much they spent on their child's last birthday gift. The…

A: See the handwritten solution

Q: If 64% of a sample of 550 people leaving a shopping mall claims to have spent over $25 create and…

A: Given,   Sample size = 550 Sample proportion = 0.64   Critical value: Using z-table, the z-critical…

Q: If n= 220, p-hat= .4, then what will be the 87.4% confidence interval for the population proportion?

A:

Q: In a survey, 21 people were asked how much they spent on their child's last birthday gift. The…

A: From the provided information, Sample size (n) = 21 Sample mean (x̅) = $46 Sample standard deviation…

Q: An arborist is interested in determining the mean diameter (in centimeters) of mature white oak…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.