а.What type of inheritance is shown in the pedigree?II2II124IVIdentify the genotypes of the following individuals:III- 2b.|-1Il- 2III-4IV-1+ vParagraphВI

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Description: а.What type of inheritance is shown in the pedigree?II2II124IVIdentify the genotypes of the following individuals:III- 2b.|-1Il- 2III-4IV-1+ vParagraphВI

Pedigree is a chart that represents members of a family affected by a genetic trait. Here, squares…

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a. What type of inheritance is shown in the pedigree? 1 II 1 2 4 II 1 2 3 4 5 IV 1 Identify the genotypes of the following individuals: III- 2 b. 1-1 Il- 2 III-4 IV-1 II + v ... Paragraph B I

Biology: The Unity and Diversity of Life (MindTap Course List)

15th Edition

ISBN:9781337408332

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter14: Chromosomes And Human Inheritance

Section: Chapter Questions

Problem 1GP: Does the phenotype indicated by the red circles and squares in this pedigree show an inheritance...

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6. Identify the mode of inheritance for the following pedigree. Provide the genotypes of indicated individuals. ? Genotypes: Il-1 IV-1 V-6 Il-2 IV-2 V-12 Il-3 IV-3 V- 14 III-1 IV-4 V-16 III-13 V- 1 V-19
2. Hemophilia is an X linked recessive trait. There is a woman who is a carrier for hemophilia and marries a man with hemophilia. a) Complete the Punnett Square (it is a google drawing so you will have to double click it to go to the drawing and type in and around the square. Hold the CONTROL (or Command) button and press the PERIOD button to write a superscript/exponent.) b) What are the possible genotypes of the children? c) Could any of their children have hemophilia? If so, would the child be male or female? Explain your reasoning.
y 301 Amelogenesis imperfecta is X-linked dominant. Affected XY individuals have extremely thin enamel on the teeth while XX carriers have grooved teeth from uneven deposition of enamel. If an unaffected XY individual were to produce children with a XX carrier partner, a. what would be the expected chance of a XY child being affected with the disease? b. what would be the expected chance of a XY child being affected with the disease?
What the grandparents' genotypes are? Why doesn’t the father (II-1) have the disease breast cancer? What is the formal name for an individual having the gene but not showing the trait? For this particular family, what is the recombination rate between the D17S74 marker and the breast cancer gene?
Consider the following pedigree. 하 3 10 (5 3 2 (a) What pattern of transmission is most consistent with this pedigree? (1) autosomal recessive, (2) autosomal dominant, (3) X-linked recessive, (4) X-linked dominant. (b) If individual V-2 marries a normal individual, and if the condition has a pene-trance of 85 percent, what is the probability that their second child will express the trait? (c) On the third line, what does the diamond with a 10 in the middle mean?
Pedigree 2: A. What is the most likely mode of inheritance of this disease? Choose from: autosomal dominant, autosomal recessive, X-linked dominant, X-linked recessive. B State the genotypes of individuals # 1 #4. C If individual #3 has another daughter with the same partner, what is the probability that this daughter will be affected (show the disease)?
II. Given the following pedigree below, use Punnett squares for each of the following possibilities: a) Autosomal recessive and b) Autosomal dominant in order to determine what is the mode of transmission of this trait. Disease allele = a or A, depending on mode of transmission of the disease respectively. Your Punnett squares should reflect what you see in generation II. Circle the mode of transmission. Note: Observe the whole pedigree. I Circle the mode of transmission 1 III 6 genotype (circle one): AA Created by Dr. Susan A. Holechek for BIO 340 (2023) 2 1 2 3 4 a) Autosomal recessive 11 x 12 9 XªXa 2 3 5 6 Ở хаха *4 7 b) Autosomal dominant 11x12 8 Aa *Unaffected/No carrier-Normal AaAa
Ill.siven the following pedigree below, use Punnett squares for each of the following possibilities: a) X- linked dominant, b) X-linked recessive, c) Autosomal dominant and d) Autosomal recessive in order to determine what is the mode of transmission of this trait. Disease allele = Xª, x², A or a depending on mode of transmission of the disease respectively. Unaffected X chromosome = X *Homozygous unaffected/No 1 *2 carrier=Normal II 1 *4 1 2 3 6. 7 8 a) X-linked dominant 11x12 b) X-linked recessive I 1 x1 2 c) Autosomal dominant 11x12 d) Autosomal recessive I1x12 IV. Based on your analysis what is the mode of transmission for this disease? O+
II. Given the following pedigree below, use Punnett squares for each of the following possibilities: a) X- linked dominant and b) X-linked recessive in order to determine what is the mode of transmission of this trait. Disease allele = XA or Xª, depending on mode of transmission of the disease respectively. *Unaffected/No carrier-Normal Unaffected X chromosome = X I || III 1 1 2 a) X-linked recessive 9 III 6 genotype (circle one): XX * 1 2 3 11x12 4 ΧΑΧΑ 2 5 xaxa *4 6 7 8 b) X-linked dominant 11 x 12 오 XAX хах
Does the phenotype indicated by the red circles and squares in this pedigree show an inheritance pattern that is autosomal dominant, autosomal recessive, or X-linked?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What if the couple wanted prenatal testing so that a normal fetus could be aborted?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?