Researchers want to examine the effect of perceived control on health complaints of geriatric patients in a long-term care facility. Thirty patients are randomly selected to participate in the study. Half are given a plant to care for and half are given a plant but the care is conducted by the staff. Number of health complaints are recorded for each patient over the following seven days. Compute the appropriate t-test for the data provided below.
Control over Plant |
No Control over Plant |
23 |
35 |
12 |
21 |
6 |
26 |
15 |
24 |
18 |
17 |
5 |
23 |
21 |
37 |
18 |
22 |
34 |
16 |
10 |
38 |
23 |
23 |
14 |
41 |
19 |
27 |
23 |
24 |
8 |
32 |
a) What would be the null hypothesis and alternative hypothesis in this study?
b) What is your tcrit (t critical value)?
c) Is there a significant difference between the two groups?
d) Interpret your answer.
e) Write out your t-value in APA format.
*ANSWER ALL PARTS OF THE QUESTION*
Trending nowThis is a popular solution!
Step by stepSolved in 6 steps
- An auditor for a local court system is tasked with comparing the rulings of two judges. The auditor needs to determine if Judge Hughes issues shorter sentences than Judge Wilson. The data below are the sentence lengths, in months, issued by each judge in their last twelve cases that dealt with operating a motor vehicle without a license. Test the claim that Judge Hughes issues shorter sentences than Judge Wilson for this particular type of case at the 0.10 level of significance. Let Judge Hughes' sentences be Population 1 and let Judge Wilson's sentences be Population 2. Assume that both populations are approximately normal and that the population variances are equal. Judge Hughes 24 30 + Judge 18 18 36 30 Wilson 12 36 36 Copy Data Step 1 of 3: State the null and alternative hypotheses for the test. Fill in the blank below. Ho :μ₁ = 1₂ Ha: ₁ 12 24 M₂ 12 30 36 18 36 36 24 12arrow_forwardThe accompanying data were read from a plot (and are a subset of the complete data set) given in an article. The data represent the mean response times for a group of individuals with closed-head injury (CHI) and a matched control group without head injury on 10 different tasks. Each observation was based on a different study, and used different subjects, so it is reasonable to assume that the observations are independent. y = Study 1 2 3 4 5 6 7 8 9 10 Mean Response Time CHI 302 492 658 684 922 1044 1421 1329 1481 1815 t = Control 250 360 475 (a) Fit a linear regression model that would allow you to predict the mean response time for those suffering a closed-head injury from the mean response time on the same task for individuals with no head injury. (Round your answers to four decimal places.) 525 610 740 880 920 1010 1200 (b) Do the sample data support the hypothesis that there is a useful linear relationship between the mean response time for individuals with no head injury and the…arrow_forwardA school principal claims that the number of students who are tardy to school does not vary from month to month. A survey over the school year produced the following results. Using a 0.01 level of significance, test a teacher's claim that the number of tardy students does vary by the month. Number Aug. Sept. Oct. 18 13 19 Tardy Students Nov. 14 Dec. Jan. Feb. Mar. Apr. May 8 6 13 11 15 16 Copy Data Step 3 of 4: Compute the value of the test statistic. Round any intermediate calculations to at least six decimal places, and round your final answer to three decimal places.arrow_forward
- Several methods of estimating the number of seeds in soil samples have been developed by ecologists. An article gave the accompanying data on the number of seeds detected by the direct method and by the stratified method for 27 soil specimens. Specimen Direct Stratified 1 21 7 2 34 38 3 0 7 4 60 58 5 20 54 6 61 61 7 40 27 8 7 7 9 14 7 10 94 100 11 1 0 12 67 58 13 78 67 14 21 54 Specimen Direct Stratified 15 34 27 16 0 0 17 38 38 18 18 14 19 94 94 20 1 14 21 40 47 22 21 21 23 0 0 24 7 14 25 14 40 26 18 14 27 40 78 Do the data provide sufficient evidence to conclude that the mean number of seeds detected differs for the two methods? Test the relevant hypotheses using ? = 0.05. (Use ?direct − ?stratified.) Find the test statistic. (Round your answer to two decimal places.) t = Find the df. (Round your answer down to the nearest whole number.) df = Use technology to find the P-value. (Round your answer to four…arrow_forwardOst watched Ani... Question 2 Y Part 1 of 4 A doctor in Cleveland wants to know whether the average life span for heart disease patients at four hospitals in the city differ. The data below represents the life span, in years, of heart disease patients from each hospital. Perform an ANOVA test with a 9% level of significance to test whether the average life span of heart disease patients in Cleveland differs depending on the hospital that treats them Life Span of Patients Treated at Hospital 1: 7.4, 7.8, 7.7, 7.5, 8, 8.2, 7.8, 8.6, 8, 7.8, 8.3, 8.3, 8, 7.6, 8.2, 7.9, 7.3, 8, 8.6, 7.3, 8.3, 8, 7.8, 8, 7.8, 8.1, 8.1, 8, 7.6, 7.6, 7.7, 7.4, 7.7, 7.8, 7.8 Life Span of Patients Treated at Hospital 2: 7.9, 7.9, 8.2, 8, 8.1, 8.5, 8.3, 8.4, 8, 8.2, 7.7, 8, 8, 7.8, 7.9, 8.1, 8.1, 7.8, 7.9, 8, 8.5, 8.3, 8.2, 8.3, 7.8, 7.9 Life Span of Patients Treated at Hospital 3: 8.2, 8.1, 7.4, 8.7, 8.6, 8.2, 7.9, 8.1, 8.1, 8.3, 8.3, 8, 7.6, 8, 7.4, 8.6, 8.2, 8.2, 7.9, 7.7, 8.1, 7.9, 8, 8.3 Life Span of…arrow_forwardPart 1 of 4 A doctor in Oklahoma City wants to know whether the average life span for heart disease patients at four hospitals in the city differ. The data below represents the life span, in years, of heart disease patients from each hospital. Perform an ANOVA test with a 10% level of significance to test whether the average life span of heart disease patients in Oklahoma City differs depending on the hospital that treats them Life Span of Patients Treated at Hospital 1: 8.1, 1.2, 7, 11.5, 21, 2, 15.3, 19.2, 10.5, 15.4, 12.7, 15.3, 12.1, 7.5, 11.4, 16.4, 26.7, 14.6, 1.5, 16.3, 12.6, 0.8, 18.2, 4.2, 9.6, 21, 16.3, 2.7 Life Span of Patients Treated at Hospital 2: 17.6, 11.6, 16.8, 5.2, 6.7, 3.2, 13.8, 12.5, 0.9, 6, 14.3, 1.8, 14.8, 10, 5.8, 15.2, 10, 3.7, 11.4, 21.6, 12.9, 0.5, 9.2, 13.9, 10.9 Life Span of Patients Treated at Hospital 3: 8.5, 2.3, 11, 7.4, 14.8, 5.8, 11, 3.4, 10.9, 1.1, 5.9, 21.6, 12.5, 0.1, 15.5, 15.4, 0.8, 7.7, 5.6, 12, 7.1 Life Span of Patients Treated at Hospital 4:…arrow_forward
- Several methods of estimating the number of seeds in soil samples have been developed by ecologists. An article gave the accompanying data on the number of seeds detected by the direct method and by the stratified method for 27 soil specimens. Specimen Direct Stratified 1 21 6 2 32 38 3 0 6 4 60 58 5 20 52 6 61 61 7 40 26 8 6 6 9 12 6 10 92 100 11 1 0 12 66 58 13 78 66 14 21 52 Specimen Direct Stratified 15 32 26 16 0 0 17 38 38 18 18 12 19 92 92 20 1 12 21 40 46 22 21 21 23 0 0 24 6 12 25 12 40 26 18 12 27 40 78 Do the data provide sufficient evidence to conclude that the mean number of seeds detected differs for the two methods? Test the relevant hypotheses using ? = 0.05. (Use ?direct − ?stratified.) Find the test statistic. (Round your answer to two decimal places.) t = Find the df. (Round your answer down to the nearest whole number.) df = Use technology to find the P-value. (Round your answer to four…arrow_forwardA school principal claims that the number of students who are tardy to school does not vary from month to month. A survey over the school year produced the following results. Using a 0.10 level of significance, test a teacher’s claim that the number of tardy students does vary by month. Tardy Students Aug. Sept. Oct. Nov. Dec. Jan. Feb. Mar. Apr. May Number 17 10 7 18 11 17 8 7 19 19 Copy Data Step 3 of 4 : Compute the value of the test statistic. Round any intermediate calculations to at least six decimal places, and round your final answer to three decimal places.arrow_forwardAlpha equals 0.01 level of significance for the given sample data.arrow_forward
- They then decided to determine whether the effect of the phone depended on how dependent people were on their phones. They had participants complete a scale to measure phone dependence (e.g., I would have trouble getting through a normal day without my phone) and classified them as high or low in dependence. They then analysed working memory task performance in a 2 (location: outside, desk) x 2(dependence: high, low) ANOVA. In this design, "dependence" is a(n) O a. Independent variable O b. Extraneous variable O c. Dependent variable O d. Subject variablearrow_forwardVineyard Pines sells clothing online. In 2020, the mean value of orders placed with the company was $34.50. The President of the company made increasing the amount of the average order a priority for 2021. The company has just received the sales data for 2021. You just received the EXCEL file with details of the 400 orders in in the first quarter of 2021. You began by calculating the univariate statistics. Here are your findings:Total sales revenue:$14,000Number of orders in 2021:400Average order: $35.00Standard deviation of the individual orders: $5.20 Required: Determine the P-Value associated with the change in the average order total in 2021. Note that the company’s strategies for growth could have led to a reduction so we cannot assume a one-directional hypothesis. Given the number of data points (orders), you can assume a normal distribution and therefore assume a z-distribution for the data.arrow_forwardAn auditor for a local court system is tasked with comparing the rulings of two judges. The auditor needs to determine if Judge Hughes issues shorter sentences than Judge Wilson. The data below are the sentence lengths, in months, issued by each judge in their last twelve cases that dealt with operating a motor vehicle without a license. Test the claim that Judge Hughes issues shorter sentences than Judge Wilson for this particular type of case at the 0.05 level of significance. Let Judge Hughes' sentences be Population 1 and let Judge Wilson's sentences be Population 2. Assume that both populations are approximately normal and that the population variances are equal. Judge 24 12 12 30 36 30 12 18 24 12 24 30 Hughes Judge Wilson 36 36 24 24 24 24 18 12 30 24 18 30 Step 3 of 3: Draw a conclusion and interpret the decision. Copy Dataarrow_forward
- MATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th...StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C...StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage Learning
- Elementary Statistics: Picturing the World (7th E...StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman