
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Transcribed Image Text:3. A vibrating mass of 0.06 kg has an amplitude of 0.08 m and a time period of 4.0 s. If the
motion is simple harmonic, calculate the following for the mass at the equilibrium
position
a) velocity,
b) acceleration,
c) kinetic energy.
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- A block on a spring slides on a horizontal frictionless surface with simple harmonic motion as shown. mim The corresponding displacement graph of the block is shown below: A- P x = A cos at -A- Submit R m 'S T U 37/4 V 1) At which point is the velocity of the block positive and the acceleration negative?arrow_forwardExplain the Simple Harmonic Motion ?arrow_forwardThe device depicted in the figure below entertains infants while keeping them from wandering. The child bounces in a harness suspended from a door frame by a spring. Jon Jemp a) If the spring stretches 0.247 m while supporting a 9.9 kg child, what is its spring constant? Number N/m b) What is the time for one complete bounce of this child? Number S c) What is the child's maximum velocity if the amplitude of her bounce is 0.18 m. Numberarrow_forward
- In the context of simple harmonic motion, why would a smaller dog's tail wag faster than a larger dog's tail?arrow_forwardA graph of harmonic motion shows that one cycle lasts from 4.3 seconds to 6.8 seconds. What is the period of this harmonic motionarrow_forwardIT WAS FOUND WHEN BOBBING FOR APPLES THAT A WHOLE CYCLE FOR BOBBING = 0.7 SECONDS INITIALLY DISPLACED BY IF THE APPLE WAS 10.03m-FIND THE FOLLOWING: GIVEN: PERIOD OF OSCILLATION OF APPLES = 0.1 SECONDS FREQUENCY OF OSCILLATION OF APPLES: 1.428 Hz ANGULAR FREQUENCY = 8.97 rad/s FIND: AMPLITUDE OF POSITION OF APPLE AFTER 5 SECONDS VELOCITY OF APPLE AFTER 5 SECONDS. ACCELERATION OF APPLE AFTER 5 SECONDS OSCILLATION = m m m/s m/s2arrow_forward
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