WHEN BOBBING FOR APPLES, IT WAS FOUND THAT A WHOLE CYCLE FOR BOBBING = 0.7 SECONDS IF THE APPLE WAS INITIALLY DISPLACED BY 0.03m-FIND THE FOLLOWING: GIVEN: PERIOD OF OSCILLATION OF APPLES = 0.7 SECONDS FREQUENCY OF OSCILLATION OF APPLES: 1.4.28 Hz ANGULAR FREQUENCY = 8.97 rad/s FIND: OSCILLATION = AMPLITUDE OF POSITION OF APPLE AFTER VELOCITY OF APPLE AFTER 5 ACCELERATION OF APPLE AFTER 5 SECONDS 5 SECONDS SECONDS. m m/s m/s 2
WHEN BOBBING FOR APPLES, IT WAS FOUND THAT A WHOLE CYCLE FOR BOBBING = 0.7 SECONDS IF THE APPLE WAS INITIALLY DISPLACED BY 0.03m-FIND THE FOLLOWING: GIVEN: PERIOD OF OSCILLATION OF APPLES = 0.7 SECONDS FREQUENCY OF OSCILLATION OF APPLES: 1.4.28 Hz ANGULAR FREQUENCY = 8.97 rad/s FIND: OSCILLATION = AMPLITUDE OF POSITION OF APPLE AFTER VELOCITY OF APPLE AFTER 5 ACCELERATION OF APPLE AFTER 5 SECONDS 5 SECONDS SECONDS. m m/s m/s 2
Related questions
Question
100%
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 19 images