WHEN BOBBING FOR APPLES, IT WAS FOUND THAT A WHOLE CYCLE FOR BOBBING = 0.7 SECONDS IF THE APPLE WAS INITIALLY DISPLACED BY 0.03m-FIND THE FOLLOWING: GIVEN: PERIOD OF OSCILLATION OF APPLES = 0.7 SECONDS FREQUENCY OF OSCILLATION OF APPLES: 1.4.28 Hz ANGULAR FREQUENCY = 8.97 rad/s FIND: OSCILLATION = AMPLITUDE OF POSITION OF APPLE AFTER VELOCITY OF APPLE AFTER 5 ACCELERATION OF APPLE AFTER 5 SECONDS 5 SECONDS SECONDS. m m/s m/s 2

5). The motion of a particle is defined by the follouing equations: ex = x-2y and dt dy =5x-y with x(0)=2 and yco) =-1 dt a. Find x(t) and yit) b. If xlt) and yct) are perniodic, find their amplitudes and peiods. Co which apaph represents the moton best? 3. う人 フイ NIETHER A 2.

You have a stationary mass attached to a compressed spring that is facing horizontal (on a frictionless plane). You give the mass a quick whack with a hammer, such that the mass has an initial velocity of 6.0 m/s. The amplitude of the oscillation of the mass is 4.0 m. How far is the mass from its starting position after 2.0 s? A) 0.50 m B) 0.56 m C) 0.78 m D) 1.0 m E) 1.1 m F) 2.0 m G) 2.3 m H) 4.0 m

Given a horizontal spring, an object with a mass of 5 kg is pulled to the right 15 cm to the right. (Observation was made that during 8 seconds 12 oscialtions occured druing the trial).  Find the postion and velocity after 1-second.  Use equation: x(t) = Acos(wt +phi) where A is max amplitude  w is angular frequency  t is time  and phi is phase