WHEN BOBBING FOR APPLES, IT WAS FOUND THAT A WHOLE CYCLE FOR BOBBING = 0.7 SECONDS IF THE APPLE WAS INITIALLY DISPLACED BY 0.03m-FIND THE FOLLOWING: GIVEN: PERIOD OF OSCILLATION OF APPLES = 0.7 SECONDS FREQUENCY OF OSCILLATION OF APPLES: 1.4.28 Hz ANGULAR FREQUENCY = 8.97 rad/s FIND: OSCILLATION = AMPLITUDE OF POSITION OF APPLE AFTER VELOCITY OF APPLE AFTER 5 ACCELERATION OF APPLE AFTER 5 SECONDS 5 SECONDS SECONDS. m m/s m/s 2

icon
Related questions
Question
100%
IT WAS FOUND
WHEN BOBBING FOR APPLES
THAT A WHOLE CYCLE FOR BOBBING = 0.7 SECONDS
INITIALLY DISPLACED
BY
IF THE APPLE WAS
10.03m-FIND THE FOLLOWING:
GIVEN: PERIOD OF OSCILLATION OF APPLES = 0.1 SECONDS
FREQUENCY OF OSCILLATION OF APPLES: 1.428 Hz
ANGULAR FREQUENCY = 8.97 rad/s
FIND:
AMPLITUDE OF
POSITION OF APPLE AFTER
5 SECONDS
VELOCITY OF APPLE AFTER 5 SECONDS.
ACCELERATION OF APPLE AFTER 5 SECONDS
OSCILLATION =
m
m
m/s
m/s2
Transcribed Image Text:IT WAS FOUND WHEN BOBBING FOR APPLES THAT A WHOLE CYCLE FOR BOBBING = 0.7 SECONDS INITIALLY DISPLACED BY IF THE APPLE WAS 10.03m-FIND THE FOLLOWING: GIVEN: PERIOD OF OSCILLATION OF APPLES = 0.1 SECONDS FREQUENCY OF OSCILLATION OF APPLES: 1.428 Hz ANGULAR FREQUENCY = 8.97 rad/s FIND: AMPLITUDE OF POSITION OF APPLE AFTER 5 SECONDS VELOCITY OF APPLE AFTER 5 SECONDS. ACCELERATION OF APPLE AFTER 5 SECONDS OSCILLATION = m m m/s m/s2
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 19 images

Blurred answer