College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A uniform magnetic field points north; its magnitude is 1.30 T. A proton with kinetic energy 3.20 × 10−13 J is moving vertically downward in this field. What is the magnetic force acting on it? If the force is toward east, enter a positive value.
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- A proton moving at 4.50 x 106 m/s through a magnetic field of magnitude 1.68 T experiences a magnetic force of magnitude 8.40 x 10-13 N. What is the angle between the proton's velocity and the field? (Enter both possible answers from smallest to largest.)arrow_forwardA typical magnitude of the external magnetic field in a cardiac catheter ablation procedure using remote magnetic navigation is B = 0.080 T. Suppose that the permanent magnet in the catheter used in the procedure is inside the left atrium of the heart and subject to this external magnetic field. The permanent magnet has a magnetic moment of 0.15 A . m². The orientation of the permanent magnet is 20° from the direction of the external magnetic field lines. (a) What is the magnitude of the torque on the tip of the catheter containing this permanent magnet? mN. m (b) What is the potential energy of the system consisting of the permanent magnet in the catheter and the magnetic field provided by the external magnets? m]arrow_forwardA positively charged particle travels in the positive x direction through a region of magnetic field in the negative y direction. In what direction is the resulting force? O negative x direction O negative z direction O positive y directionarrow_forward
- A proton traveling at 24.7° with respect to the direction of a magnetic field of strength 2.33 mT experiences a magnetic force of 6.38 × 10-17 N. Calculate (a) the proton's speed and (b) its kinetic energy in electron-volts.arrow_forwardi know the direction of the magnetic force on a proton is in the negative y direction and the direction of the magnetic force on an electron is in the positive y directionarrow_forwardChapter 28, Problem 018 GO In the figure, a particle moves along a circle in a region of uniform magnetic field of magnitude B = 4.5 mT. The particle is either a proton or an electron (you must decide which). It experiences a magnetic force of magnitude 2.8 × 10-15 N. What are (a) the particle's speed, (b) the radius of the circle, and (c) the period of the motion? O Chapter 28, Problem 020 An electron is accelerated from rest through potential difference V and then enters a region of uniform magnetic field, where it undergoes uniform circular motion. The figure gives the radius r of that motion versus V¹/2. The vertical axis scale is set by rs= 4.0 mm, and the horizontal axis scale is set by V₁¹/2= 32.9 V¹/2. What is the magnitude of the magnetic field? (աա) 0 1/2 (1/2)arrow_forward
- A proton moving at 4.30 x 10° m/s through a magnetic field of magnitude 1.62 T experiences a magnetic force of magnitude 8.80 x 105 N. What is the angle between the proton's velocity and the field? (Enter both possible answers from smallest to largest.)arrow_forwardA proton moving at 4.80 x 106 m/s through a magnetic field of magnitude 1.76 T experiences a magnetic force of magnitude 7.00 × 10-¹3 N. What is the angle between the proton's velocity and the field? (Enter both possible answers from smallest to largest. Enter only positive values between 0 and 360.) smaller value larger value O Oarrow_forwardWhich describes the net force on a magnetic dipole in a uniform magnetic field? The net force vector is in the direction of the magnetic field. O The net force vector is in the direction opposite that of the magnetic field. The net force vector is perpendicular to the direction of the magnetic field. O The net force vector is zero.arrow_forward
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