Chapter 28, Problem 018 GO In the figure, a particle moves along a circle in a region of uniform magnetic field of magnitude B = 4.5 mT. The particle is either a proton or an electron (you must decide which). It experiences a magnetic force of magnitude 2.8 × 10-15 N. What are (a) the particle's speed, (b) the radius of the circle, and (c) the period of the motion? O B

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Chapter29: Magnetic Fields
Section: Chapter Questions
Problem 29.80CP: A proton moving in the plane of the page has a kinetic energy of 6.00 MeV. A magnetic field of...
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Chapter 28, Problem 018 GO
In the figure, a particle moves along a circle in a region of uniform
magnetic field of magnitude B = 4.5 mT. The particle is either a proton or
an electron (you must decide which). It experiences a magnetic force of
magnitude 2.8 × 10-15 N. What are (a) the particle's speed, (b) the
radius of the circle, and (c) the period of the motion?
O
Chapter 28, Problem 020
An electron is accelerated from rest through potential difference V and
then enters a region of uniform magnetic field, where it undergoes
uniform circular motion. The figure gives the radius r of that motion
versus V¹/2. The vertical axis scale is set by rs= 4.0 mm, and the
horizontal axis scale is set by V₁¹/2= 32.9 V¹/2. What is the magnitude of
the magnetic field?
(աա)
0
1/2 (1/2)
Transcribed Image Text:Chapter 28, Problem 018 GO In the figure, a particle moves along a circle in a region of uniform magnetic field of magnitude B = 4.5 mT. The particle is either a proton or an electron (you must decide which). It experiences a magnetic force of magnitude 2.8 × 10-15 N. What are (a) the particle's speed, (b) the radius of the circle, and (c) the period of the motion? O Chapter 28, Problem 020 An electron is accelerated from rest through potential difference V and then enters a region of uniform magnetic field, where it undergoes uniform circular motion. The figure gives the radius r of that motion versus V¹/2. The vertical axis scale is set by rs= 4.0 mm, and the horizontal axis scale is set by V₁¹/2= 32.9 V¹/2. What is the magnitude of the magnetic field? (աա) 0 1/2 (1/2)
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