A charged particle (q=1.609 x 10-19 C) moves through a uniform magnetic field whose magnitude is 2.0T.  The field is directly parallel to the positive x-axis.  What is the magnitude and direction of the force when the particle moves in the negative y-direction with a speed of 4.0 x 104 m/s? Sketch the x-, y- and z-axes and show the direction of the magnetic field, the magnetic force and the velocity.

An alpha particle has a positive charge that is double the charge of a proton, and a mass of 6.64 ✕ 10−27 kg. At a particular instant, it is moving with a speed of 5.00 ✕ 106 m/s through a magnetic field. At this instant, its velocity makes an angle of 55° with the direction of the magnetic field at the particle's location. The magnitude of the field is 0.170 T.   a) What is the magnitude of the magnetic force (in N) on the particle? b)What is the magnitude of the particle's acceleration (in m/s2) at this instant?

An electron moves at speed 8.00 × 10^5 m/s in a plane perpendicular to a cyclotron’s magnetic field. The magnitude of the magnetic force on the electron is 1.10 × 10^−13 N. What is the magnitude of the magnetic field?

A charged particle enters a region with uniform magnetic field and leaves in a perpendicular with respect to initial direction. Find the sign and the speed of the charged particle is B=3,22 T, m=7,17x10 21 kg, q=8e and the distance travelled in the magnetic field is I=4,11 cm, where e is charge of one electron. IX X x X XI B ix x X x a. positive, 1504,12 cm/s b. negative, 1128,09 cm/s c. positive, 752,06 cm/s d. negative, 1504,12 cm/s e. positive, 1128,09 cm/s

In the figure below, a proton enters a region of downward and constant magnetic field B. While in the field, the proton travels a distance of d = 1.05 cm. The proton has a speed of 1.35 km/s. Notice the perpendicularity of entrance and exit of the proton. Calculate the magnitude of the magnetic field B (in tesla). NOTE: Final answer in FIVE decimal places. IX X X X X B IX X X

Magnetic Fields: A particle with a charge of +8.4 µC and a speed of 45 m/s enters a uniform magnetic field B whose magnitude is 0.30 T. Find the magnitude and direction of the magnetic force on the particle when its velocity makes a 30º with respect to the direction of B.

a proton is moving through a magnetic field in a direction perpendicular to the field as shown below. The magnetic field has a magnitude of B= 0.13 T and the charge experiences a force of F= 9.98 x 10^-14 N. How fast and in what direction is it moving? The charge of a proton is qp= +1.6x 10^-19 C.

A 1500 kg car moves west along the equator. At this location Earth's magnetic field is 3.5 × 10^−5 T and points north parallel to Earth's surface. If the car carries a charge of -2.5 × 10^−3 C, how fast must it move so that the magnetic force balances 0.010% of Earth's gravitational force exerted on the car?

Consider the following figures. (a) Find the direction of the force on a proton (a positively charged particle) moving through the magnetic fields in the figure, as shown. Field Force Direction a         b         c         d         e         f         Force Direction can be left, right, up , down, into page or out of page (b) Repeat part (a), assuming the moving particle is an electron. Field Force Direction a         b         c         d         e         f         Force Direction can be left, right, up , down, into page or out of page

A particle with a charge of 31 μC moves with a speed of 76 m/s in the positive x direction. The magnetic field in this region of space has a component of 0.43 T in the positive y direction, and a component of 0.87 T in the positive z direction. What is the magnitude of the magnetic force on the particle? What is the direction of the magnetic force on the particle? (Find the angle measured from the positive z-axis toward the negative y-axis in the yz-plane.)