College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- A hinged beam, 92.5 kg, is supported by a horizontal cable as in the figure. The length of the cable is 2.00 m and the length of the beam is 3.00 m. Find: (a) the torque produced by gravity on the beam, (b) the tension in the cable, (c) the horizontal and vertical components of the force from the hinge, and (d) the magnitude and direction of the force from the hinge.arrow_forwardA 10.0 m long rod, with a mass which acts at its center, supports three weights as shown. Where is its center of gravity? X kg Y kg 0.0 5.0 m Z kg 10.0 m where X = 5.00, Y = 15.0, and Z=30.0.arrow_forwardComputation A 6-kg bowling ball rests on a uniform beam of length L and mass M, as in the figure. The beam is supported at two points separated by a distance BL where ß = 0.59 and the bowling ball is a distance d from support point 1. Find the largest distance dmax such that the beam does not tip if M = 17 kg and L = 4.9 m. [Note: To keep the bowling ball on the beam, report an answer of dmax ≤ L. For some values, a correct calculation gives dmax > L. That means the bowling ball can be placed anywhere on the beam without tipping and, in that case, the correct answer is dmax = L = 4.9 m.) 2 dmax m L BL- d M Report your numerical answer below, assuming three significant figures. Remember to include a "-" as necessary. O Search 1arrow_forward
- A beam resting on two pivots has a length of L = 6.00 m and mass M = 77.0 kg. The pivot under the left end exerts a normal force n1 on the beam, and the second pivot placed a distance ℓ = 4.00 m from the left end exerts a normal force n2. A woman of mass m = 61.5 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip. (a) Use the force equation of equilibrium to find the value of n2 when the beam is about to tip. (b) Using the result of part (c) and the torque equilibrium equation, with torques computed around the second pivot point, find the woman's position when the beam is about to tip.x = (c) Check the answer to part (e) by computing torques around the first pivot point.x = (d)Except for possible slight differences due to rounding, is the answer the same for F and E?arrow_forwardA rod with a length L = 1.0 m long and a mass of 6.0 kg is pivoted around its center. A force of magnitude F = 5.0 N and angle 30° is applied at one end of the rod. A second force of magnitude F/2 is applied 0.25 m from the pivot at an angle of 53° as shown below. F 30⁰ m 53⁰ -pivot F/2 L/2 What is the magnitude of the angular acceleration due to the applied forces? L/4arrow_forwardThe angle between the beam and the floor is 15.0 degrees. The angle between the rope and the horizontal is 31.0 degrees. The beam is 4.10-m long and has a mass of 6.10 kg. The box sits a distance of d = 0.770 m from the upper end of the beam and has a mass of 9.60 kg.What is the torque due only to the weight of the box if the axis is at the hinge?arrow_forward
- A beam resting on two pivots has a length of L = 6.00 m and mass M = 87.0 kg. The pivot under the left end exerts a normal force n₁ on the beam, and the second pivot placed a distance = 4.00 m from the left end exerts a normal force n₂. A woman of mass m = 52.0 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip. -L- m M (a) Sketch a free-body diagram, labeling the gravitational and normal forces acting on the beam and placing the woman x meters to the right of the first pivot, which is the origin. (Submit a file with a maximum size of 1 MB.) Choose File No file chosen (b) Where is the woman when the normal force n₁ is the greatest? x = L m (c) What is n, when the beam is about to tip? N (d) Use the force equation of equilibrium to find the value of n₂ when the beam is about to tip. N (e) Using the result of part (c) and the torque equilibrium equation, with torques computed…arrow_forwardA uniform 8.00 m, 1500 kg beat is hinged to a wall and supported by a thin cable attached 2.00 m from the free end of the beam. The beam is fixed to the wall by a hinge at an angle of 30.0 degrees above the horizontal. The angle between the cable and the beam is 40 degrees. What is the direction of the torque exerted by the beam around the point where the cable is attached? -clockwise -counterclockwisearrow_forwardA 2.0 m long, 200 N uniform ladder, rests with one end against a smooth wall making an angle of 30° with the wall. The coefficient of static friction between the ground and the lower end of the ladder is 0.5. A force F pushes the upper end of the ladder parallel to the wall so that the ladder is on the verge of starting to slip down (static friction has reached its maximum value). The torque of the weight of the ladder relative to the lower end in the ground is: a. 200 Nm b. 620 Nm C. 546 Nm d. 400 Nm e. None of the above Iarrow_forward
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