A rod with a length L = 1.0 m long and a mass of 6.0 kg is pivoted around its center. A force of magnitude F = 5.0 N and angle 30° is applied at one end of the rod. A second force of magnitude F/2 is applied 0.25 m from the pivot at an angle of 53° as shown below. F 30⁰ m 53⁰ -pivot L/4 F/2 L/2 What is the magnitude of the angular acceleration due to the applied forces?

A sign for a pizza restaurant hangs from a 2.60-m long rod extended out from a building. A cable, attached to the building, is attached to the rod at a point that is 2.10 m from the hidge. (See the figure.)The mass of the rod is 6.50 kg. The mass of the sign is 9.40 kg. The angle between the building and the rod is 73.0 degrees. The angle between the cable and the horizontal is 30.0 degrees.What is the torque on the rod due to the weight of the sign alone? [Take the axis to be at the hinge.]

Two children of mass 25 kg and 26 kg sit balanced on a seesaw with the pivot point located at the center of the seesaw. If the children are separated by a distance of 3.0 m, at what distance, in meters, from the pivot point is the smaller child sitting in order to maintain the balance?

A gymnast with a mass of 54 kg stands on the end of a uniform balance beam as shown in the figure.  The beam is 5.50 m long and has a mass of 250 kg.  Each support is 0.54m from the end of the beam.  What is the force on the beam due to support 2?

In exercise physiology studies, it is sometimes important to determine the location of a person's center of mass. This determination can be done with the arrangement shown in the figure below. A light plank rests on two scales, which read F, = 395 N and F, gi = 340 N. A distance of 1.65 m separates the scales. How far from the woman's feet is her center of mass? g2 1.65 m F 18. F 82

Three children are playing on a seesaw. The largest child has a mass of 50 kg and sits on the right side of the seesaw 0.9 m from the fulcrum. The middle child has a mass of 40 kg and sits on the left side of the seesaw 2.5 m from the fulcrum. Where does the smallest child, who has a mass of 25 kg, need to sit in order to balance the seesaw?

In the figure, what magnitude of force F applied horizontally at the axle of the wheel is necessary to raise the wheel over an obstacle of height h = 0.267 m? The wheel's radius is r = 0.673 m and its mass is m = 1.75 kg. DF

A beam resting on two pivots has a length of L = 6.00 m and mass M = 79.0 kg. The pivot under the left end exerts a normal force n, on the beam, and the second pivot placed a distance l = 4.00 m from the left end exerts a normal force n,. A woman of mass m = 59.5 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip. M (a) Sketch a free-body diagram, labeling the gravitational and normal forces acting on the beam and placing the woman x meters to the right of the first pivot, which is the origin. (Submit a file with a maximum size of 1 MB.) Choose File No file chosen This answer has not been graded yet. (b) Where is the woman when the normal force n, is the greatest? X = (c) What is n, when the beam is about to tip? N (d) Use the force equation of equilibrium to find the value of n, when the beam is about to tip. N (e) Using the result of part (c) and the torque equilibrium…

A seesaw has length 11.0 m and uniform mass 11.3 kg and is resting at an angle of 30° with respect to the ground (see the following figure). The pivot is located at 8.3 m from the end of the seesaw. What magnitude of force (in N) needs to be applied perpendicular to the seesaw at the raised end so as to allow the seesaw to barely start to rotate? F=? 30 N t

12 m 12 m A 3 m B 3 m Figure 1 Figure 2 A simple trebuchet is constructed as shown above.The projectile mass, ma = M = 1.50 kg, and the counterweight mass, mg = cM, where c is 7.50 x 102. Relative to the masses of the projectile and counterweight, the mass of the rotating arm is assumed negligible and there is no friction in the pivot.There is a mechanism that stops the arm when it becomes vertical, allowing the projectile to be launched horizontally. {If needed, treat both masses as point masses with moment of inertia = (mass)R2.} a. Determine the tangential speed of the projectile at the top of the motion as it leaves the trebuchet. Blank 1 b. How long is the projectile is in the air? Blank 2 Do Not Enter Units In Answers. Show All Starting Equations And Ideas That Lead To Your Answers. Blank 1 Add your answer Blank 2 Add your answer