A rod with a length L = 1.0 m long and a mass of 6.0 kg is pivoted around its center. A force of magnitude F = 5.0 N and angle 30° is applied at one end of the rod. A second force of magnitude F/2 is applied 0.25 m from the pivot at an angle of 53° as shown below. F 30⁰ m 53⁰ -pivot L/4 F/2 L/2 What is the magnitude of the angular acceleration due to the applied forces?

A rod with a length L = 1.0 m long and a mass of 6.0 kg is pivoted around its center. A force of magnitude F = 5.0 N and angle 30° is applied at one end of the rod. A second force of magnitude F/2 is applied 0.25 m from the pivot at an angle of 53° as shown below. F 30⁰ m 53⁰ -pivot L/4 F/2 L/2 What is the magnitude of the angular acceleration due to the applied forces?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Torque

Torque is the rotational equivalent of linear force in physics and mechanics. Based on the course of study, it is also known as the moment of force, rotational force, or turning effect.

Question

A rod with a length L = 1.0 m long and a mass of 6.0 kg is pivoted around its
center. A force of magnitude F = 5.0 N and angle 30° is applied at one end of
the rod. A second force of magnitude F/2 is applied 0.25 m from the pivot at an
angle of 53° as shown below.
F
30⁰
m
53⁰
-pivot
F/2
L/2
What is the magnitude of the angular acceleration due to the applied forces?
L/4

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