MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- A sociologist claims that the students’ college GPA’s in unrelated to their families’ incomes. For a random sample of 20 students the coefficient of correlation was computed as 0.40. Using the 0.01 significance level, do the formal hypothesis test.Remember to show your steps (including all relevant information) show the steps on how to solve itarrow_forwardSuppose that we are interested in comparing the academic success of college students who belong to fraternal organizations and the academic success of those who do not belong to fraternal organizations. Random samples of size 40 are taken from each population where the variances and standard deviations are known. Sample Size Mean GPA Variance (2) 2.03 2.21 Fraternity member (f): 40 Nonmembers (n): 40 .46 .35 Construct a 96% confidence interval estimate for the difference between the mean GPAS (uf- un). Interpret this interval estimate. What can you conclude about the mean GPAs of the two groups?arrow_forwardCadmium, a heavy metal, is toxic to animals. Mushrooms, however, are able to absorb and accumulate cadmium at high concentrations. Some governments have a safety limit for cadmium in dry vegetables at 0.56 part per million (ppm). A research team measured the cadmium levels in a random sample of edible mushrooms, where the hypothesis test is to decide whether the mean cadmium level in the sample is greater than the governments' safety limit. The null and alternative hypotheses are H0: μ=0.56 ppm, Ha: μ>0.56 ppm. Complete parts (a) through (e) below. d. Now suppose that the results of carrying out the hypothesis test lead to nonrejection of the null hypothesis. Classify that conclusion by error type or as a correct decision if in fact the mean cadmium level in that type of mushrooms equals the safety limit of 0.56 ppm. Choose the correct answer below. A. type I error B. correct decision because a true null hypothesis is not rejected C. correct decision because…arrow_forward
- Use the data and table below to test the indicated claim about the means of two populations. Assume that the two samples are independent simple randor samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Make sure you identify all values. An Exercise Science instructor at IVC was interested in comparing the resting pulse rates of students who exercise regularly and the pulse rates of those who de not exercise regularly. Independent simple random samples of 16 students who do not exercise regularly and 12 students who exercise regularly were selected and the resting pulse rates (in beats per minute) were recorded. The summary statistics are presented in the table below. Is there compelling statistical evidence that the mean resting pulse rate of people who do not exercise regularly is greater than the mean resting pulse rate of people who exercise regularly? Use a significance value of 0.05. Two-Sample T-Test Sample…arrow_forwardA company is doing a hypothesis test on the variation in quality from two suppliers. Both distributions are normal, and the populations are independent. Use a = 0.05. A sample of 31 products were selected from Supplier 1 and a standard deviation of quality was found to be 3.77. A sample of 16 products were selected from Supplier 2 and a standard deviation of quality was found to be 3.5659. Test to see if the variance in quality for Supplier 1 is larger than Supplier 2. What are the correct hypotheses? Note this may view better in full screen mode. Select the correct symbols in the order they appear in the problem. Ho: 0.² H₁: 0.² Based on the hypotheses, compute the following: Round answers to at least 4 decimal places. The test statistic is = The p-value is = The decision is to [Fail to reject the null hypothesis The correct summary would be: There is not enough evidence to support the claim in quality for Supplier 1 is larger than Supplier 2. o that the variancearrow_forwardGn. don't provide handwriting solutionarrow_forward
- A simple random sample of 95 basketball players is taken from different teams and their mean weight is found to be 226 pounds and the standard deviation of the population is 20 pounds. Using 0.05 level of significance, test the claim that the average weight for all basketball players is 231 pounds. Complete the following steps: Step # 1: Write the null hypothesis Ho [ Select ] and the alternative hypothesis H1 [ Select ] and identify the claim [Select] Step # 2: Indicate what type of test has to be used [Select ] and find the critical value(s). ( Select ] Step # 3: Find the test value. [ Select ] Step # 4: Make the decision about the null hypothesis. [ Select ] Step # 5: Summarize the result. (Select Jarrow_forwardA coin-operated drink machine was designed to discharge a mean of 9 ounces of coffee per cup. Suppose that we want to carry out a hypothesis test to see if the true mean discharge differs from 9 . State the null hypothesis H0 and the alternative hypothesis H1 that we would use for this test.arrow_forwardExecutives of a supermarket chain are interested in the amount of time that customers spend in the stores during shopping trips. The mean shopping time, μ , spent by customers at the supermarkets has been reported to be 36 minutes, but executives hire a statistical consultant and ask her to determine whether it can be concluded that μ is greater than 36 minutes. The consultant plans to do a statistical test and collects a random sample of 50 shopping times at the supermarkets. Suppose that the population of shopping times at the supermarkets has a standard deviation of 16 minutes and that the consultant performs her hypothesis test using the 0.05 level of significance.arrow_forward
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