A student prepared the graph shown based on the vapor pressure of a liquid over a range of temperatures. The best fit line was found to have the equation y = –1978x + 12.4 Use this data to calculate the heat of vaporization of the liquid.

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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A student prepared the graph shown based on the vapor
107
pressure of a liquid over a range of temperatures. The best fit
line was found to have the equation
9-
8-
y = –1978x + 12.4
y =-1978x + 12.4
7-
Use this data to calculate the heat of vaporization of
the liquid.
3-
kJ/mol
heat of vaporization =
2-
1-
0-
0.002
0.003
0.004
0.005
0.006
1/T (K)
In P (mmHg)
Transcribed Image Text:A student prepared the graph shown based on the vapor 107 pressure of a liquid over a range of temperatures. The best fit line was found to have the equation 9- 8- y = –1978x + 12.4 y =-1978x + 12.4 7- Use this data to calculate the heat of vaporization of the liquid. 3- kJ/mol heat of vaporization = 2- 1- 0- 0.002 0.003 0.004 0.005 0.006 1/T (K) In P (mmHg)
Expert Solution
Step 1

Heat of vaporization is the heat required to vaporize one mol of substance at its boiling point. 

Clausius-Clapeyron equation relates natural logarithm of vapor pressure, lnP with absolute temperature, T. Mathematically, the equation is as shown below:

dlnPdT=HvapRT2

Here, Hvap is enthalpy of vaporization and R is universal gas constant.

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