Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Related questions
Concept explainers
Question
Transcribed Image Text:A student prepared the graph shown based on the vapor
107
pressure of a liquid over a range of temperatures. The best fit
line was found to have the equation
9-
8-
y = –1978x + 12.4
y =-1978x + 12.4
7-
Use this data to calculate the heat of vaporization of
the liquid.
3-
kJ/mol
heat of vaporization =
2-
1-
0-
0.002
0.003
0.004
0.005
0.006
1/T (K)
In P (mmHg)
Expert Solution
arrow_forward
Step 1
Heat of vaporization is the heat required to vaporize one mol of substance at its boiling point.
Clausius-Clapeyron equation relates natural logarithm of vapor pressure, lnP with absolute temperature, T. Mathematically, the equation is as shown below:
Here, is enthalpy of vaporization and R is universal gas constant.
Trending nowThis is a popular solution!
Step by stepSolved in 2 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Four liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain th order of their boiling points. For example, select '1' in the second column next to the liquid with the lowest freezing point. Select '2' in the second column next to the liquid with the next higher freezing point, and so on. In the third column, select '1' next to the liquid with the lowest boiling point, '2' next to the liquid with the next higher boiling point, and so on. Note: the density of water is 1.00 g/mL. solution freezing point boiling point 3.6 g of calcium chloride (CaCl2) dissolved in 300. mL of water (choose one)v (choose one) v (choose one) (choose one) 3.6 g of propylene glycol (C3H8O2) dissolved in 300. mL of water 3.6 g of glucose (C6H1206) dissolved in 300. mL of water 300. mL of pure water (choose one) 4(highest) く (choose one) 1(lowest) x 5arrow_forwardFour liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain the order of their boiling points. For example, select '1' in the second column next to the liquid with the lowest freezing point. Select '2' in the second column next to the liquid with the next higher freezing point, and so on. In the third column, select '1' next to the liquid with the lowest boiling point, '2' next to the liquid with the next higher boiling point, and so on. Note: the density of water is 1.00 g/mL. solution 2.2 g of ethylene glycol (C₂H602) dissolved in 200. mL of water 2.2 g of sucrose (C12H22011) dissolved in 200. mL of water 2.2 g of potassium nitrate (KNO3) dissolved in 200. mL of water 200. mL of pure water freezing point (choose one) (choose one) (choose one) (choose one) X boiling point (choose one) (choose one) O (choose one) (choose one)arrow_forwardFour liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain the order of their boiling points. For example, select '1' in the second column next to the liquid with the lowest freezing point. Select '2' in the second column next to the liquid with the next higher freezing point, and so on. In the third column, select '1' next to the liquid with the lowest boiling point, '2' next to the liquid with the next higher boiling point, and so on. Note: the density of water is 1.00 g/mL. solution 6.0 g of ethylene glycol (C₂H6O2) dissolved in 200. mL of water 6.0 g of potassium sulfate (K₂SO4) dissolved in 200. mL of water 6.0 g of sucrose (C12H22011) dissolved in 200. mL of water 200. mL of pure water freezing point ✓ (choose one) 1(lowest) 2 3 4(highest) (choose one) X boiling point (choose one) (choose one) (choose one) (choose one) Śarrow_forward
- An ice cube with a mass of 45.4 g at 0.0 °C is added to a glass containing 374 g of water at 45.0 °C. Determine the final temperature of the system at equilibrium. The specific heat capacity of water, C, is 4.184 J/g.°C, and the standard enthalpy of fusion, AH; , of water is 6.01 × 10° J/mol. Assume that no energy is transferred to or from the surroundings. fus T = °C TOOLS x10 Question Source: Atkins 7e - Chemical Principles| Publisher: W.H. Frearrow_forwardTwo 20.0 g ice cubes at −12.0 ∘C−12.0 ∘C are placed into 275 g275 g of water at 25.0 ∘C.25.0 ∘C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, ?f,Tf, of the water after all the ice melts.arrow_forwardFour liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain the order of their boiling points. For example, select '1' in the second column next to the liquid with the lowest freezing point. Select '2' in the second column next to the liquid with the next higher freezing point, and so on. In the third column, select '1' next to the liquid with the lowest boiling point, '2' next to the liquid with the next higher boiling point, and so on. Note: the density of water is 1.00 g/mL. solution freezing point boiling point 7.3 g of glycerin (C3H8O3) dissolved in 100. mL of water (choose one) (choose one) 7.3 g of glucose (C6H1206) dissolved in 100. mL of water (choose one) (choose one) 7.3 g of potassium iodide (KI) dissolved in 100. mL of water (choose one) (choose one) 100. mL of pure water (choose one) (choose one)arrow_forward
- 90. The normal boiling point of water is 100.00 °C and the enthalpy of vaporization at this temperature is ¢vapH = 40.657 kJ mol-1. What would be the boiling point of water if it were based on a pressure of 1 bar instead of the standard atm?arrow_forwardThe following compounds are liquid at -10 °C: diethyl ether, methanol, and ethylene glycol. Arrange the three compounds in order of increasing vapor pressure at -10 °C. Choose between 1 - lowest vapor pressure, 2, or 3 - highest vapor pressure. Note: Reference the Phase change properties of pure substances table for additional information. Ethylene glycol (Choose one) Methanol (Choose one) Diethyl ether (Choose one) Garrow_forwardIn addition to filling in the blanks below, show all of your work for this problem on paper for later upload. The heat of vaporization of isopropanol is 44.0 kJ/mol. The vapor pressure of isopropanol at 400 torr is 67.8 °C. Calculate the normal boiling point of isopropanol. Enter your value in the first box and an appropriate unit of measure in the second box.arrow_forward
- Carbon tetrachloride, CCI4 , has a vapor pressure of 213 torr at 40.°C and 971 torr at 85°C. What is the normal boiling point of CCI4? Boiling point =arrow_forwardA 0.580 g0.580 g sample of steam at 107.3 ∘C107.3 ∘C is condensed into a container with 4.56 g4.56 g of water at 17.0 ∘C.17.0 ∘C. What is the final temperature of the water mixture if no heat is lost? The specific heat of water is 4.18 J g⋅ ∘C,4.18 J g⋅ ∘C, the specific heat of steam is 2.01 J g⋅ ∘C,2.01 J g⋅ ∘C, and Δ?vap=40.7 kJ/mol.arrow_forwardFour liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain the order of their boiling points. For example, select '1' in the second column next to the liquid with the lowest freezing point. Select '2' in the second column next to the liquid with the next higher freezing point, and so on. In the third column, select '1' next to the liquid with the lowest boiling point, '2' next to the liquid with the next higher boiling point, and so on. Note: the density of water is 1.00 g/mL. solution freezing point boiling point 6.4 g of glucose (C6H1206) dissolved in 300. mL of water (choose one) O (choose one) 6.4 g of potassium sulfate (K2SO4) dissolved in 300. mL of water (choose one) (choose one) O 6.4 g of sodium bromide (NaBr) dissolved in 300. mL of water (choose one) (choose one) O 300. mL of pure water (choose one) E (choose one) Earrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning 
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY