Two converging lenses having focal lengths of f₁ = 11.9 cm and f₂ = 20.0 cm are placed d₁ = 53.5 cm apart, as shown in the figure below. Object Final image

An object is placed 66 cm in front of a converging lens of focal length 9 cm. Another converging lens of focal length 14 cm is placed 26 cm behind the first lens. a) Find the position of the final image with respect to the second lens. cm b) Find the magnification of the final image.

= A glass lens with an index of refraction of n = 1.52 cm has a front surface with a radius of curvature of R₁ has a back surface with a radius of curvature of R₂ = -18.7 cm. What is the focal length of this lens? cm b. Is this lens converging or diverging? ONLY 1 ATTEMPT IS ALLOWED FOR THIS PART. ---Select-- 16.2 cm, and

= 3. A 15 cm tall object sits 80 cm to the left of a converging lens with a focal length of fi 30 cm. There is a second converging lens with a focal length of f2 = 20 cm sitting 60 cm to the right of the first converging lens. dige de a. Where is the image from the first lens formed? (find di1) f₁ = 30 cm do = 80cm di = ? C. -14 1-do₂ 'वे di = [130 - 50 ] = 48 cm to the right of lens 1 = b. What is the object distance for the second lens? (find doz) f₂ =20 cm do=48 cm di = ? Where is the final image formed? (find diz) do d. What is the distance between the original object and the final image? What is the overall magnification for this two-lens system? f. What is the height of the final image? (find hi2) 2

A 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal length 7.80 cm. A diverging lens of focal length –16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position 7.5 cm in front of the second lens v 0.5466 height Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final image. cm Is the image inverted or upright? upright O inverted Is the image real or virtual? real virtual

Q1 a) The eyepiece of a refracting telescope has a focal length of 9.00cm. The distance between objective and eyepiece is 1.80m, and the final image is at infinity. What is the angular magnification of the telescope? F=580×10² 14

Homework 12 Problem 10:   Two lenses are mounted d = 27 cm apart on an optical bench. The focal length of the first lens is f1 = 5.1 cm and that of the second lens is f2 = 4.4 cm. An object of height ho = 3.5 cm is placed at a distance of do = 21 cm in front of the first lens. Part (a)  Ignoring the second lens for now, at what distance, in centimeters, behind the first lens is the object’s image formed by that lens? di = ______ Part (b)  Calculate the magnification of that image, including its sign. m = ______ Part (c)  Now consider the two-lens system and the final image it forms, i.e., the image created by the second lens. What is the distance, in centimeters, between the object and its final image? D = ______

Two converging lenses having focal lengths of f1 = 10.8 cm and f2 = 19.7 cm are placed d1 = 53.6 cm apart, as shown in the figure below.A) The final image is to be located between the lenses at d2 = 29.1 cm. How far to the left of the first lens should the object be positioned? B) What is the overall magnification?

A 7.75 mm high chocolate chip is placed on the axis of, and 13.9 cm from, a lens with a focal length of 6.91 cm. If it can be determined, is the chocolate chip's image real or virtual? virtual real cannot be determined How high is the image? Express the answer as a positive quantity. image height: mm

A converging lens has a focal length of 29 cm. An object is placed 10.2 cm in front of the lens. What is the location of the image? cm b. What is the magnification? c. Is the image upright, or inverted? ONLY 1 ATTEMPT IS ALLOWED FOR THIS PART. --Select-v d. Is the image in front of the lens, or behind the lens? ONLY 1 ATTEMPT IS ALLOWED FOR THIS PART. --Select-- v