A student determines the value of the equilibrium constant to be 4.09×10-18 for the following reaction. Fe;O4(s) + 4H2(g)→3FE(s) + 4H,O(g) Based on this value of Kegi AG° for this reaction is expected to be (greater, less) greater than zero. Calculate the free energy change for the reaction of 1.76 moles of Fe;0,(s) at standard conditions at 298K. AG°. rxn = 190.5 kJ

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Chapter16: Thermodynamics: Directionality Of Chemical Reactions
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A student determines the value of the equilibrium constant to be 4.09×10-18 for the following reaction.
Fe;O4(s) + 4H2(g)→3FE(s) + 4H,O(g)
Based on this value of Kegi
AG° for this reaction is expected to be (greater, less) greater
than zero.
Calculate the free energy change for the reaction of 1.76 moles of Fe;0,(s) at standard conditions at 298K.
AG°.
rxn
= 190.5
kJ
Transcribed Image Text:A student determines the value of the equilibrium constant to be 4.09×10-18 for the following reaction. Fe;O4(s) + 4H2(g)→3FE(s) + 4H,O(g) Based on this value of Kegi AG° for this reaction is expected to be (greater, less) greater than zero. Calculate the free energy change for the reaction of 1.76 moles of Fe;0,(s) at standard conditions at 298K. AG°. rxn = 190.5 kJ
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