A staggered bolted connection has bolts arranged as shown. Diameter of bolts is 21 mm. Fy = 248 MPa. Calculate the net area (sq. mm) along fracture line passing through bolts 2 and 3 only. Use w = 4.8 x100 mm and t = 16 mm.
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- An A36 tension plate is 15 mm thick is given below. Bolts are 16 mm. Given that s = 90 mm and g = 70 mm, calculate the net area at tensile fracture line d-e-b-c in mm2. Write your answer rounded to the nearest whole number. 50 | 50 +S +S 50 g 50A staggered bolted connection has bolts arranged as shown. Diameter of bolts is 19 mm. Fy = 248 MPa. Calculate the net area (sq. mm) along fracture line passing through bolts 2 and 3 only. Use w = 4.9 mm and t = 18 mm. Write your final answer in whole numberSITUATION 14: A PL 300 x 20 mm is to be connected to two plates of the same material with half the thickness by 25 mm Ø rivets as shown in the figure. The rivet holes have a diameter 2 mm larger than the rivet diameter. The plate is A36 steel with Fy= 250 MPa, allowable tensile stress of 0.60Fy and allowable bearing stress of 1.35Fy. The rivets are A502, Grade 2, hotdriven rivets with allowable shear stress of 150 MPa. 25 mm Ø rivets + + PL 300x20 P/2 P P/2 PL 300x10 43. Which of the following most nearly gives the max. load in kN that can be applied to the connection without exceeding the allowable shear stress in the rivets? a. 675 KN b. 490 KN c. 598 KN d. 790.5 kN 44. Which of the following most nearly gives the max. load in kN that can be applied to the connection without exceeding the allowable bearing stress between the plates and the rivets? a. 490 KN b. 675 KN c. 598 KN d. 790.5 kN 45. Which of the following most nearly gives the max. load in kN that can be applied to the…
- 26 60mm, 60mm 100mm 100mm 100mm 100mm A staggered bolted connection has bolts arranged as shown. Diameter of bolts is 19 mm. Fy = 248 MРа. Calculate the net area (sq. mm) along fracture line passing through bolts 2 and 3 only. Use w = 4.5 mm and t = 19 mm. Write your final answer in whole numberAn A36 tension member shown in the figure is connected with three 19 mm diameter bolts. Dia. Of bolt hole = 22 mm. %3D 50, 100 100 99.45 T- 50.55 100 Properties of 150 mm x 100 mm x 12.5 mm angle A = 3065 mm? y = 50.55 mm Fy = 248 MPa Fu = 400 MPa Determine the design strength due to fracture in the net section. UseU 0.85. (kN)The tension member shown in the figure is an A36 steel plate 16 mm thick. The bolts are 22 mm in diameter. Calculate the following: 49. Determine the net area (mm^2) across fracture line a-b-f-g. The damaged hole diameter is 4mm larger than the bolt diameter.
- An A36 tension plate is 9 mm thick is given below. Bolts are 20 mm. Given that s = 50 mm and g = 75 mm, calculate the net area at tensile fracture line d-e-b-f-g in mm2. Write your answer rounded to the nearest whole number.W 10x45 is connected to two plates with two lines of ¾” bolts as shown below. Determine the tensile strength of the system if Fy = 50 ksi and Fu = 65 ksi.Question 27 An A36 angle bar is used as a tension member connected on both legs with 18 mm diameter bolts. Given that s = 65 mm, calculate the design strength (kN) by LRFD with the limiting state of tensile fracture at the smallest possible net area. Write your answer to the nearest whole number. Ag = 1,852 mm2 t = 8 mm
- Problem. A bolted connection shown consists of two plates 300 mm x 12 mm connected by 4 - 22 mm diameter bolts. 12 mm bolts T12 mm te12 mm P 300 75 75 75 Edge distances = 75 mm %3D dnole for tensile and rupture = dp +3 mm %3D dnole for bearing strength for Lec = d + 1.5 mm Fy = 248 MPa Fu = 400 MPa %3D En 330 MPa %3D Use LRFD design method. Determine the design strength due to tensile rupture strength of plates. (kN)An A36 tension member shown in the figure is connected with three 19 mm diameter bolts. Dia. Of bolt hole = 22 mm. %3D 50, 100 100 99.45 50.55 100 Properties of 150 mm x 100 mm x 12.5 mm angle A - 3065 mm- y - 50.55 mm Fy - 248 MPa Fu 400 MPa Determine the design strength due to yielding in the gross section. (kN)Plate t = 8mm C230x19.9 M20 Bolts Ag = 2,530 mm? d = 229 mm T 80 tw = 5.90 mm bf = 61 mm tr = 10.5 mm F, = 345 MPa x = 15 mm F = 450 MPa 60 80 80 60 From the figure shown, which of the following most nearly gives the block shear strength? O 679,7 KN O 1.013.8 KN O 872.9 KN 691.4 KN