A spring-loaded piston-cylinder device contains of m=1 kg carbon dioxide. Initially, the spring has no force on the piston and , , . Heat is transferred to the gas, causing the piston to rise and to compress the spring. At the state 2, , . The gas is an ideal gas. (9) If cv=0.657kJ/kg·K, calculate the internal energy ch

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A spring-loaded piston-cylinder device contains  of m=1 kg carbon dioxide. Initially, the spring has no force on the piston and , , . Heat is transferred to the gas, causing the piston to rise and to compress the spring. At the state 2,  , . The gas is an ideal gas.

 (9) If cv=0.657kJ/kg·K, calculate the internal energy change ΔU=mcv(T2-T1)______(kJ)

 

A spring-loaded piston-cylinder device contains \( m = 1 \, \text{kg} \) carbon dioxide. Initially, the spring has no force on the piston and \( P_1 = 500 \, \text{kPa}, \, T_1 = 150 \, \text{K}, \, V_1 = 0.1 \, \text{m}^3 \). Heat is transferred to the gas, causing the piston to rise and compress the spring. At state 2, \( T_2 = 900 \, \text{K}, \, V_2 = 0.3 \, \text{m}^3 \). The gas is an ideal gas.

(9) If \( c_v = 0.657 \, \text{kJ/kg} \cdot \text{K} \), calculate the internal energy change \(\Delta U = mc_v(T_2 - T_1) \) _____ (kJ).

---

**Graphs Explanation:**

There are two diagrams shown:

1. **Diagram on the Left:** This represents state 1 of the piston-cylinder setup.
   - A piston-cylinder with a relaxed spring (no compression or tensile force).
   - Labels at the bottom: \( P_1, V_1, T_1 \).

2. **Diagram on the Right:** This represents state 2 of the piston-cylinder after heat transfer.
   - The spring is shown compressed with the piston moved upwards.
   - Labels at the bottom: \( P_2, V_2, T_2 \).

Both diagrams are simplified illustrations of the initial and final states of the system, highlighting the volumetric change and spring compression due to heat addition.
Transcribed Image Text:A spring-loaded piston-cylinder device contains \( m = 1 \, \text{kg} \) carbon dioxide. Initially, the spring has no force on the piston and \( P_1 = 500 \, \text{kPa}, \, T_1 = 150 \, \text{K}, \, V_1 = 0.1 \, \text{m}^3 \). Heat is transferred to the gas, causing the piston to rise and compress the spring. At state 2, \( T_2 = 900 \, \text{K}, \, V_2 = 0.3 \, \text{m}^3 \). The gas is an ideal gas. (9) If \( c_v = 0.657 \, \text{kJ/kg} \cdot \text{K} \), calculate the internal energy change \(\Delta U = mc_v(T_2 - T_1) \) _____ (kJ). --- **Graphs Explanation:** There are two diagrams shown: 1. **Diagram on the Left:** This represents state 1 of the piston-cylinder setup. - A piston-cylinder with a relaxed spring (no compression or tensile force). - Labels at the bottom: \( P_1, V_1, T_1 \). 2. **Diagram on the Right:** This represents state 2 of the piston-cylinder after heat transfer. - The spring is shown compressed with the piston moved upwards. - Labels at the bottom: \( P_2, V_2, T_2 \). Both diagrams are simplified illustrations of the initial and final states of the system, highlighting the volumetric change and spring compression due to heat addition.
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