Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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  1. Shown in the figure, an insulated rigid tank is divided into two equal parts by a partition. Initially, one part contains an indeal gas, and the other part is evacuated. The partition is then removed, and the gas expands into the entire tank. At the initial state, the mass of the gas is m= 4.00kg, initial pressure is p1 = 600.00 kPa, initial temperature is T1 = 300.00 K. The gas constant is R = 0.7180 kJ/(kg·K). (The internal energy can be determined by the equation ΔU=m·cv·(T2-T1), where c=  0.7180 kJ/(kg·K) is the specific heat at the constant volume.)

    Calculate the internal energy change ΔU.__________ (kJ)



     

Shown in the figure, an insulated rigid tank is divided into two equal parts by a partition. Initially, one part contains an indeal gas, and the other part is
evacuated. The partition is then removed, and the gas expands into the entire tank. At the initial state, the mass of the gas is m= 4.00kg, initial pressure
is p1 = 600.00 kPa, initial temperature is T1 = 300.00 K. The gas constant is R = 0.7180 kJ/(kg-K). (The internal energy can be determined by the
equation AU=m-cy (T2-T1), where cy= 0.7180 kJ/(kg-K) is the specific heat at the constant volume.)
Calculate the internal energy change AU.
Ideal gas
T1
FISE
P1
V1
m
State 1
Evacuated
(kJ)
Ideal gas
T2=?
P2=?
V2=2V1
State 2
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Transcribed Image Text:Shown in the figure, an insulated rigid tank is divided into two equal parts by a partition. Initially, one part contains an indeal gas, and the other part is evacuated. The partition is then removed, and the gas expands into the entire tank. At the initial state, the mass of the gas is m= 4.00kg, initial pressure is p1 = 600.00 kPa, initial temperature is T1 = 300.00 K. The gas constant is R = 0.7180 kJ/(kg-K). (The internal energy can be determined by the equation AU=m-cy (T2-T1), where cy= 0.7180 kJ/(kg-K) is the specific heat at the constant volume.) Calculate the internal energy change AU. Ideal gas T1 FISE P1 V1 m State 1 Evacuated (kJ) Ideal gas T2=? P2=? V2=2V1 State 2
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