Shown in the figure, an insulated rigid tank is divided into two equal parts by a partition. Initially, one part contains an indeal gas, and the other part is evacuated. The partition is then removed, and the gas expands into the entire tank. At the initial state, the mass of the gas is m= 4.00kg, initial pressure is p1 = 600.00 kPa, initial temperature is T1 = 300.00 K. The gas constant is R = 0.2870 kJ/(kg·K). (The internal energy can be determined by the equation ΔU=m·cv·(T2-T1), where cv = 0.7180 kJ/(kg·K) is the specific heat at the constant volume.) Calculate the volume of the tank. Vtotal__________ (m3) In the figure, an insulated rigid tank is divided into two equal parts by a partition. Initially, one part contains an ideal gas, while the other part is evacuated. The partition is then removed, allowing the gas to expand into the entire tank.Initial Conditions (State 1):- Pressure (\(P_1\)): 600.00 kPa- Temperature (\(T_1\)): 300.00 K- Volume (\(V_1\)): \(V\)- Mass (\(m\)): 4.00 kgGas Properties:- Gas constant (\(R\)): 0.2870 kJ/(kg·K)Final Conditions (State 2):- Temperature (\(T_2\)): ?- Pressure (\(P_2\)): ?- Volume (\(V_2\)): \(2V_1\)Energy Calculation:The internal energy change (\(\Delta U\)) can be determined using the equation:\[\Delta U = m \cdot c_V \cdot (T_2 - T_1)\]where \(c_V = 0.7180\) kJ/(kg·K) is the specific heat at constant volume.Task:Calculate the total volume of the tank (\(V_{\text{total}}\)) in m³. The figure consists of two diagrams depicting the system's states:- **State 1**: Represents the initial condition where one side of the tank contains the ideal gas and the other is evacuated.- **State 2**: Shows the gas occupying the entire tank after the partition is removed, indicating that the volume is doubled.

Giveninsulated tankm=4kgP1=600kPaT1=300KR=0.287 kJ/kgKCv=0.7180 kJ/kgK∆U=mCvT2-T1

Answered: Shown in the figure, an insulated rigid…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Shown in the figure, an insulated rigid tank is divided into two equal parts by a partition. Initially, one part contains an indeal gas, and the other part is evacuated. The partition is then removed, and the gas expands into the entire tank. At the initial state, the mass of the gas is m= 4.00kg, initial pressure is p1 = 600.00 kPa, initial temperature is T1 = 300.00 K. The gas constant is R = 0.2870 kJ/(kg·K). (The internal energy can be determined by the equation ΔU=m·c_v·(T₂-T₁), where c_v= 0.7180 kJ/(kg·K)is the specific heat at the constant volume.)

Calculate the volume of the tank. V_total__________ (m³)

In the figure, an insulated rigid tank is divided into two equal parts by a partition. Initially, one part contains an ideal gas, while the other part is evacuated. The partition is then removed, allowing the gas to expand into the entire tank.

Initial Conditions (State 1):
- Pressure (\(P_1\)): 600.00 kPa
- Temperature (\(T_1\)): 300.00 K
- Volume (\(V_1\)): \(V\)
- Mass (\(m\)): 4.00 kg

Gas Properties:
- Gas constant (\(R\)): 0.2870 kJ/(kg·K)

Final Conditions (State 2):
- Temperature (\(T_2\)): ?
- Pressure (\(P_2\)): ?
- Volume (\(V_2\)): \(2V_1\)

Energy Calculation:
The internal energy change (\(\Delta U\)) can be determined using the equation:
\[
\Delta U = m \cdot c_V \cdot (T_2 - T_1)
\]

where \(c_V = 0.7180\) kJ/(kg·K) is the specific heat at constant volume.

Task:
Calculate the total volume of the tank (\(V_{\text{total}}\)) in m³.

The figure consists of two diagrams depicting the system's states:
- **State 1**: Represents the initial condition where one side of the tank contains the ideal gas and the other is evacuated.
- **State 2**: Shows the gas occupying the entire tank after the partition is removed, indicating that the volume is doubled.

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