A solution composed of 50% ethanol (ETOH), 10% methanol (MEOH), and 40% water (H20) is fed at the rate of 100 kg/hr into a separator that produces one stream at the rate of 60 kg/hr with the composition of 80% ETOH, 15% MEOH, and 5% H20, and a second stream of unknown composition. Calculate the composition (in %) of the three compounds in the unknown stream and its flowrate in kg/hr. F = 100 kg/hr mass fr >P 60 kg/hr mass fr Separator EIOH 0.80 MEOH 0.15 ELOH 0.50 МеОН 0.10 H,0 0.40 H,0 0.05 1.00 W = ? kg/hr %3D 1.00 kg/hr or mass fr ELOH OEIOH MEOH MMEOH OMEOH H,0 mH,0 WH,O W 1.00

An organic chemistry student isolates 738 mg of salicylic acid (SA) and decides to use methanol in an attempt to purify it by recrystallization. Use the following information to calculate the maximum amount (in mg) that can purified from the crude product. SA solubility in methanol: o°C = 41.3 g/100 mL 56 °C = 64.5 g/100 mL

synthetic ion exchange resins. These resins are organic polymeric networks that contain functional groups that are permanently attached to the resin. One such functional group is sulfonic acid, -SO3H. When placed in water, the resin (being a large organic molecule) will not dissolve. However, the ionic functional groups become hydrated and the resin will swell as it takes up waters of hydration. The resin may then be thought of as a solid solution mixture with the functional groups being "dissolved" but the polymer remaining as a solid. The hydronium ion (H3O+) associated with acidic functional groups like sulfonic acid will dissociate just as it would if the acid were free of the resin. If other cations such as Cu2+ or Na+ are added to the resin, an ion-exchange reaction can occur:  . Note that one H+ is released for each positive charge bound to the resin.  Since the resin exchanges a hydrogen ion for a sodium ion in this reaction, sulfonic acid resins are called cation-exchange…

A polymer of large molar mass is dissolved in the organic solvent dimethylformamide (C3H7NO) at 25 °C, and the resulting solution rises to a final height of 10.8 cm above the level of the pure solvent, as solvent molecules pass through a semipermeable membrane into the solution. If the solution contains 3.80 g polymer per liter, calculate the molar mass of the polymer. Take the density of the solution to be 0.944 g cm-³. Molar mass polymer = g mol-1

Transfer 0.5 mL phenolphthalein to a flask 25 mL KHP. Then transfer 13.2mL NaOH in the KHP that make it be pink. As the picture shows. Now, show a complete calculation for the concentration of the sodium hydroxide solution.

Answer provided: 33.8-ppm K^+1 Please show your complete solution and write your answer clearly and readable. Thank you.

A certain dilute solution has an osmotic pressure of 11.1 atm at 25°C. Calculate the difference between the chemical potential of the solvent in the solution and that of pure water. Assume that the density is the same as that of water at 25°C, 0.99705 g-cm-3. (Hint: Express the chemical potential in terms of mole fraction, x1, and rewrite the osmotic pressure equation as OV = n2RT, where n2 is the number of moles of the solute and V = 1.00 L.)

Given: Mass of lauric acid (g): 8.000g Mass of benzoic acid (g): 1.027g Freezing temperature of pure lactic acid(°C): 43.3°C Freezing point of the benzoic acid-lauric acid mixture(°C): 39.8°C   Question: Calculate molality (m,) in mol/kg, using the formula ΔTf = m × Kf. The Kf value for lauric acid is 3.9°C x kg/mol.