A simply supported wood beam with a span of L = 14 ft supports a uniformly distributed load w. The beam width is b = 7 in. and the beam height is h = 14 in. The allowable bending stress of the wood is 810 psi. Determine the magnitude of the maximum load w that may be carried by the beam. Answer: w = Mi lb/ft.

A double tee cross section is used for the beam shown below. Assume the following lengths and loads: a = 16 ft b = 8 ft c = 12 ft P= 9000 lb Q = 3000 Ib The moment of inertia of the cross section is l, = 110 in.“. Determine the magnitude (i.e., the absolute value) of the maximum tensile bending stress in the beam. 3.2 in. B C D 5.8 in. Answer: Omax (Tension) : i psi

M = 2. A beam of length 10 m and of uniform rectangular section is supported at its ends and carries uniformly distributed load over the entire length. Calculate the depth of the section if the maximum permissible bending stress is 16 N/mm² and central deflection is not to exceed 10 mm. Take the value of E = 1.2 × 104 N/mm². Use the following g equations: w.L² 8 ус W.L 161 8 d = 2 W.L 8 == WL³ 5 384 ΕΙ (: W = w.L)

If Mz = 715 kip-ft, find the magnitude of the bending stress at a point H.    For the beam cross section, assume a = 10 in. b = 14 in. d = 39 in. r = 5 in.   The centroid of the cross section is located 17.9 in. below the uppermost surface of the beam.  The moment of inertia about the z axis is 60436 in.4.