(e) Are X and Y independent rv's? Explain. Ox and Y are independent because P(x, y) = Px(x) · Py(y). OX and Y are not independent because P(x, y) = Px(x) · Py(y). OX and Y are independent because P(x, y) OX and Y are not independent because P(x, y) Px(x) · Py(y). Px(x) ·Py(y). A service station has both self-service and full-service islands. On each island, there is a single regular unleaded pump with two hoses. Let X denote the number of hoses being used on the self-service island at a particular time, and let Y denote the number of hoses on the full-service island in use at that time. The joint pmf of X and Y appears in the accompanying tabulation. p(x, y) 0 1 2 0 0.10 0.05 0.01 x 1 0.06 0.20 0.07 2 0.06 0.14 0.31 (a) What is P(X = 1 and Y = 1)? P(X = 1 and Y = 1) = | (b) Compute P(X ≤ 1 and Y < 1). P(X ≤1 and Y < 1) = (c) Give a word description of the event { X0 and Y + 0 }. One hose is in use on one island. One hose is in use on both islands. At least one hose is in use at both islands. At most one hose is in use at both islands. Compute the probability of this event. P(X +0 and Y 0) = [ (d) Compute the marginal pmf of X. x 0 Px(x) Compute the marginal pmf of Y. y Py(y) 0 Using Px(x), what is P(X ≤ 1)? P(X ≤ 1) = = 1 2 1 2

Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
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Chapter1: Computer Networks And The Internet
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Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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(e) Are X and Y independent rv's? Explain.
Ox and Y are independent because P(x, y) = Px(x) · Py(y).
OX and Y are not independent because P(x, y) = Px(x) · Py(y).
OX and Y are independent because P(x, y)
OX and Y are not independent because P(x, y)
Px(x) · Py(y).
Px(x) ·Py(y).
Transcribed Image Text:(e) Are X and Y independent rv's? Explain. Ox and Y are independent because P(x, y) = Px(x) · Py(y). OX and Y are not independent because P(x, y) = Px(x) · Py(y). OX and Y are independent because P(x, y) OX and Y are not independent because P(x, y) Px(x) · Py(y). Px(x) ·Py(y).
A service station has both self-service and full-service islands. On each island, there is a single regular unleaded pump with
two hoses. Let X denote the number of hoses being used on the self-service island at a particular time, and let Y denote the
number of hoses on the full-service island in use at that time. The joint pmf of X and Y appears in the accompanying
tabulation.
p(x, y)
0 1 2
0 0.10 0.05 0.01
x
1 0.06 0.20 0.07
2 0.06 0.14 0.31
(a) What is P(X = 1 and Y = 1)?
P(X = 1 and Y = 1) = |
(b) Compute P(X ≤ 1 and Y < 1).
P(X ≤1 and Y < 1) =
(c) Give a word description of the event { X0 and Y + 0 }.
One hose is in use on one island.
One hose is in use on both islands.
At least one hose is in use at both islands.
At most one hose is in use at both islands.
Compute the probability of this event.
P(X +0 and Y 0) = [
(d) Compute the marginal pmf of X.
x
0
Px(x)
Compute the marginal pmf of Y.
y
Py(y)
0
Using Px(x), what is P(X ≤ 1)?
P(X ≤ 1) =
=
1
2
1
2
Transcribed Image Text:A service station has both self-service and full-service islands. On each island, there is a single regular unleaded pump with two hoses. Let X denote the number of hoses being used on the self-service island at a particular time, and let Y denote the number of hoses on the full-service island in use at that time. The joint pmf of X and Y appears in the accompanying tabulation. p(x, y) 0 1 2 0 0.10 0.05 0.01 x 1 0.06 0.20 0.07 2 0.06 0.14 0.31 (a) What is P(X = 1 and Y = 1)? P(X = 1 and Y = 1) = | (b) Compute P(X ≤ 1 and Y < 1). P(X ≤1 and Y < 1) = (c) Give a word description of the event { X0 and Y + 0 }. One hose is in use on one island. One hose is in use on both islands. At least one hose is in use at both islands. At most one hose is in use at both islands. Compute the probability of this event. P(X +0 and Y 0) = [ (d) Compute the marginal pmf of X. x 0 Px(x) Compute the marginal pmf of Y. y Py(y) 0 Using Px(x), what is P(X ≤ 1)? P(X ≤ 1) = = 1 2 1 2
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