F(A, B, C, D) = Σm(0, 1, 2, 3, 9, 10, 13, 14) G(A, B, C, D) = Σm(0, 1, 8, 9, 10, 12, 13, 14) H = AD′ + A′B′C + ABC Using the functions from the previous section, encode F, G, and H using the following PLA.

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Using the three-variable Karnaugh-map below Solve for its corresponding function expression Replot the function from part (1) on a different three-variable Karnaugh-map (Hint: try a different combination of variables)

For the function, F(x, y, z) = (x+z)'+(y'z)+(xz)' find its complement. Select one: 1. (xz)' II. (x + y)' III. (xz')' IV. (x' + y + z')' V. xyz O IV. V Oll 01 OIV

1. Simplify the following Boolean functions, using three-variable Kmaps: (a) F(x, y, z) = Σ(0, 1, 5, 7) (b) F(x, y, z) = Σ(1, 2, 3, 6, 7) (c) F(x, y, z) = Σ(2, 3, 4, 5)

2. Assume you have the following truth tables for functions F₁(x, y, z) and F₂(x, y, z): X y 0 0 0 0 1 1 1 1 oK NOH 0 0 0 1 1 1 0 0 0 1 1 0 1 1 0 F₁ --| 1 1 0 0 0 1 0 0 F2 ононононл 1 1 1 1 a) Express F₁ and F₂ in sum-of-products form b) Simplify each function

Construct table of minterms and maxterms for 4 variables - x,y,z,w Obtain the truth table of the following functions, and express each function in sum-of-minterms (canonical SOP) and product-of-maxterms ( canonical POS) form: a) (xy+z)(y+x'z) b) (x+y)(y'+z) c) x'z+wx'y+wyz'+w'y' d) (xy+yz'+x'z)(x+z) Simplify the following Boolean functions T1 and T2 to a minimum number of literals: T2 0 0 0 1 1 1 1 1 A OOO 0 0 0 LLLL 1 1 1 1 B 0 0 1 1 0 0 1 1 C 0 1 0 1 0 1 اهای 1 T1 1 1 1 0 0 0 0 0

F please.

3. Use the Karnaugh-Map to simplify the following expressions F(A, B, C) = ABC + ABC + ABC + ABC + ABC F(A,B,C,D) = A + AB + ABC + BCD + ACD ii.

9. Given the following Boolean Function: F(A, B, C) = AB+B(Ā+C) Determine the canonical form for the SOP (sum of minterms) and POS (product of maxterms). Also, draw the truth tables showing the minterms and maxterms.