A sample of 16 small bags of the same brand of candies was selected. Assume that the population distribution of bag weights is normal. The weights of each bag was then recorded. The mean weight was two ounces with a standard deviation of 0.12 ounces. The population standard deviation is known to be 0.1 ounce. (a) Identify the following: X Sx

Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.5 parts/million (ppm). A researcher believes that the current ozone level is at an excess level. The mean of 66 samples is 7.7 ppm with a standard deviation of 1.0 Does the data support the claim at the 0.025 level? Assume the population distribution is approximately normal. Step 2 of 5 :   Find the value of the test statistic. Round your answer to three decimal places. Specify if the test is one-tailed or two-tailed. Determine the decision rule for rejecting the null hypothesis. Round your answer to three decimal places. Make the decision to reject or fail to reject the null hypothesis.

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Suppose baby kittens' weights are normally distributed with a mean of 11.4 and a standard deviation of 2.1. The Z-score tells you how many units above the average (if Z-score is positive) or below the average (if Z- Score is negative) any particular baby kitten's weight is. Find the baby kitten weight that corresponds to the following Z-scores. Use the formula Z where u is the mean, o is the standard deviation, and X is the baby kitten weight. a. Z = = 0.07, X = b. Z = 1.63, X =

A normal distribution has mean 62.1 and standard deviation 2.42. Find the data value corresponding to the following value of z.   z= -1.33

The mean height of females in a certain country is 66 inches with a standard deviation of 4 inches. Find the height that correspond to a z score of 0.8. Round your answer to one decimal place, if needed.