A distribution of values is normal with a mean of 235 and a standard deviation of 14.4. Find P63, which is the score separating the bottom 63% from the top 37%.

A distribution of values is normal with a mean of 202 and a standard deviation of 91.5.Find P75, which is the score separating the bottom 75% from the top 25%.P75 =

Use z scores to compare the given values. In a recent awards ceremony, the age of the winner for best actor was 34 and the age of the winner for best actress was 50. For all best actors, the mean age is 46.9 years and the standard deviation is 6.9 years. For all best actresses, the mean age is 35.6 years and the standard deviation is 11.4 years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning the award, the actor or the actress? Explain. Since the z score for the actor is z= and the z score for the actress is z= the had the more extreme age. (Round to two decimal places.)

A normal distribution has a mean of 148 and a standard deviation of 5. Find the z-score for a data value of 136.

Use z scores to compare the given values.   In a recent awards​ ceremony, the age of the winner for best actor was 34 and the age of the winner for best actress was 43. For all best​ actors, the mean age is 42.5 years and the standard deviation is 6.2 years. For all best​ actresses, the mean age is 31.9 years and the standard deviation is 11.2 years.​ (All ages are determined at the time of the awards​ ceremony.) Relative to their​ genders, who had the more extreme age when winning the​ award, the actor or the​ actress? Explain.       Question content area bottom Part 1 Since the z score for the actor is z=enter your response here and the z score for the actress is z=enter your response here​, the ▼   actress actor had the more extreme age. ​(Round to two decimal​ places.)

Use z scores to compare the given values. In a recent awards ceremony, the age of the winner for best actor was 33 and the age of the winner for best actress was 47. For all best actors, the mean age is 44.4 years and the standard deviation is 6.5 years. For all best actresses, the mean age is 32.8 years and the standard deviation is 11.2 years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning the award, the actor or the actress? Explain. Since the z score for the actor is z= and the z score for the actress is z = the V had the more extreme age. (Round to two decimal places.)

The lifespans of lizards in particular zoo are normally distributed. The average lizard lives 3.1 yearsthe standard deviation is 0.6 years. Find the probability that the lizards live longer than 3.1 years or less than 2.5 yearsHint: Draw and label a normal curve and use the percentages of the standard deviations. Write your answer using only numbers and do not include units. For example 95.3% would be entered as 95.3

A normal distribution has a mean of 140 and a standard deviation of 7. Find the z-score for a data value of 141.

Scores on a recent NYS Standardized Exam were normally distributed with a mean of 77.6 and a standard deviation of 4.3. Find the NYS Standardized Exam score that separates the bottom 2.5% from the rest. Round this score to the nearest tenth

The distribution of heights in a population of women is approximately normal. Sixteen percent of the women have heights less than 62 inches. About 97.5% of the women have heights less than 71 inches. Use the empirical rule to estimate the mean and standard deviation of the heights in this population. Mean: K inches Standard Deviation: inches