MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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Assume that the readings at freezing on a bundle of thermometers are
P26 =
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- Assume that the readings on the thermometers are normally distributed with a mean of 0°and standard deviation of1.00°C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to P91,the 91stpercentile. This is the temperature reading separating the bottom 91% from the top 9%.arrow_forwardAssume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P26, the 26-percentile. This is the temperature reading separating the bottom 26% from the top 74%.P26 = °C(Round answer to three decimal places)arrow_forwardAssume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P34, the 34-percentile. This is the temperature reading separating the bottom 34% from the top 66%. P34 =arrow_forward
- Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P29, the 29-percentile. This is the temperature reading separating the bottom 29% from the top 71%.P29 = °C(Round answer to three decimal places)arrow_forwardAssume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P9, the 9-percentile. This is the temperature reading separating the bottom 9% from the top 91%.arrow_forwardAssume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P61, the 61-percentile. This is the temperature reading separating the bottom 61% from the top 39%. P61 = °C Submit Questionarrow_forward
- Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P80, the 80-percentile. This is the temperature reading separating the bottom 80% from the top 20%.P80 = °Carrow_forwardAssume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P33, the 33-percentile. This is the temperature reading separating the bottom 33% from the top 67%. P33 = %3Darrow_forwardAssume that thermometer readings are normally distributed with a mean of 0degrees°C and a standard deviation of 1.00degrees°C. A thermometer is randomly selected and tested. (The given values are in Celsius degrees.) Between -1.47and 1.76arrow_forward
- Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P61, the 61-percentile. This is the temperature reading separating the bottom 61% from the top 39%.P61 =arrow_forwardAssume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P30, the 30-percentile. This is the temperature reading separating the bottom 30% from the top 70%.P30 = °C(Round answer to three decimal places)arrow_forwardA manufacturer of light bulbs finds that one light bulb model has a mean life span of 1026 h with a standard deviation of 86 h.Find the z-score for lightbulbs which last 910 h. (Round your answer to two decimal places.) 910 h: z =arrow_forward
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