A rubber pad is sandwiched between two steel plates subjected to shear force V = 400kN. The dimensions of the plate area, a= 250mm and b = 300mm. The thickness of the rubber is c = 125mm. After the force is applied, the top plate is found to have displaced laterally by δ = 1.5mm along the 300mm length. Determine the shear stress. Determine the shear strain. Determine the shear modulus.

The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.0 lb/in.³ is the specific weight of the material, y = 2.8 in. is the distance from the free (i.e., bottom) end of the bar, L = 14 in. is the length of the bar, and E = 20000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar (c) the maximum normal strain in the bar. Answer: (a) 8- i (b) Eavg (c) Emax = i x10-6 in. με με

The brake pads for a bicycle tire are made of rubber. If a frictional force of 50 N is applied to each side of the tires, determine the average shear strain in the rubber. Each pad has cross-sectional dimensions of 20 mm and 50 mm.Gr = 0.20 MPa.

The strain components for a point in a body subjected to plane strain are ɛ, = -460 µe, ɛ, = -990µe and Yy = 219 prad. Using Mohr's circle, determine the principal strains (sp1 > Ep2), the maximum inplane shear strain yip, and the absolute maximum shear strain ymax at the point. Show the angle e, (counterclockwise is positive, clockwise is negative), the principal strain deformations, and the maximum in-plane shear strain distortion in a sketch. Answers: Ep1 = με. Ep2 = με. Yip= prad. Ymax prad.

The man has a mass of 84 kg and stands motionless at the end of the diving board. Figure -1.5 m B -2.5 m 30 mm 350 mm 20 mm 10 mm 10 mm 10 mm Part A If the board has the cross section shown, determine the maximum normal strain developed in the board. The modulus of elasticity for the material is E 127 GPa. Assume A is a pin and 13 is a roller. B (Figure 1) C= IVE ΑΣΦ Submit ↓↑ vec Previous Answers Request Answer Ć MADE * Incorrect; Try Again; 5 attempts remaining Return to Assignment Provide Feedback ? mm/mm

The spherical pressure vessel has an inner diameter of 2 m and a thickness of 10 mm. A strain gage having a length of 20 mm is attached to it, and it is observed to increase in length by 0.012 mm when the vessel is pressurized. Determine the pressure causing this deformation, and find the maximum in-plane shear stress, and the absolute maximum shear stress at a point on theouter surface of the vessel. The material is steel, for which Est = 200 GPa and nst = 0.3.

A steel cable is used to support an elevator cage at the bottom of a 2100-ft-deep mineshaft. A uniform normal strain of 240 μin./in. is produced in the cable by the weight of the cage. At each point, the weight of the cable produces an additional normal strain that is proportional to the length of the cable below the point. Assume D = 2100 ft and d = 500 ft. If the total normal strain in the cable at the cable drum (upper end of the cable) is 790 μin./in., determine (a) the strain in the cable at a depth of 500 ft. (b) the total elongation of the cable. Drum Cable Answers: (a) ε = (b) 8 = i i d D Elevator cage X uin./in. in.

A strain gage is mounted to the outer surface of a thin-walled boiler. The boiler has an inside diameter of 1820_mm and a wall thickness of 18 mm, and it is made of stainless steel [E = 179 GPa; v = 0.3]. Determine: (a) the internal pressure in the boiler when the strain gage reads 210 µɛ. (b) the maximum shear strain in the plane of the boiler wall. (c) the absolute maximum shear strain on the outer surface of the boiler. Answers: (a) p = i MPа. (b) Ymax in-plane = i prad. (c) Yabs max i prad. =

The 45° strain rosette is mounted on the surface of a shell. The following readings are obtained for each gage: Pa = -200(10-6), Pb = 300(10-6), and Pc = 250(10-6). Determine the in-plane principal strains.

The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.9 lb/in.³ is the specific weight of the material, y = 0.5 in. is the distance from the free (i.e., bottom) end of the bar, L = 5 in. is the length of the bar, and E = 25000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar.