A rectifier circuit is used to charge a 12 Vdc battery using a 40 Vpp AC source, according to the following circuit. 1.Assuming practical diodes in the full-wave rectifier, describe the behaviour of a single diode as a p-n junction, then analyse the operation of the entire rectifier assuming 0.7-V threshold voltage for each diode (practical). 2.Build a full-wave rectifier circuit with four diodes to perform the charging function. Explain the operation of the diodes and the entire circuit. Use drawings to illustrate how battery current changes with the input voltage. (Assume that diodes turn on at 0 V (ideal))

A rectifier circuit is used to charge a 12 Vdc battery using a 40 Vpp AC source, according to the following circuit. 1.Assuming practical diodes in the full-wave rectifier, describe the behaviour of a single diode as a p-n junction, then analyse the operation of the entire rectifier assuming 0.7-V threshold voltage for each diode (practical). 2.Build a full-wave rectifier circuit with four diodes to perform the charging function. Explain the operation of the diodes and the entire circuit. Use drawings to illustrate how battery current changes with the input voltage. (Assume that diodes turn on at 0 V (ideal))

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter30: Dc Motors

Section: Chapter Questions

Problem 6RQ: What is CEMF?

See similar textbooks

Similar questions

What is CEMF?
Q5) The schematic circuit in PLECS for a single-phase rectifier is shown below, Q5) The schematic circuit in PLECS for a single-phase rectifier is shown below, Thyristor Crout Probe Pulse Generator VC, pulses Probe Scope Thy Orso v Joad O R: 1 The output voltage across R is depicted in 0.5 0.0- b) 0.2 0.0 d)
Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to IL-DC =0:5A RL VL-DC =20V 220V omsb O 001 F O 0.02 F O 0.0167F O None of the above Activate
A load is connected in the Full Bridge rectifier circuit (Four Diodes). Usedtransformer primary voltage value is 220 V (rms). The transformer winding ratio is 1:10.Using the 0.7 V model of the diode,Load Value: Student No. Last 1 digit ( will be selected as kΩ, LastThose whose number is "0" get "9")a) How many % of conduction does each diode branch stay on?b) Find the average values of the load voltage.c) Find the average values of the load current.d) Find the effective value of the load voltage.e) Find the effective value of the load current.
A three phase full wave rectifier is shown below along with peak phase voltage Vm-169.7V. The load is purely resistive. The rectifier delivers Ipc = 100 A and the source frequency is 60 Hz. The DC output voltage is %3D VDc=280.7V and the output RMS voltage is equal to VRMS=280.93V. The efficiency, FF and RF are respectively equal to: Secondary D D D, R AD. Z D. D, Select one: O a. 99.83%, 100.08%, 4% O b. 99.83%, 55.08%, 4% O C. 99.83%, 100.08%, 16% O d. 87.83%, 100.08%, 4%
Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V ams 5OHZ İL-DC =05A RL VL-DC =20V
Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V omsh RL VI-DC20V 0.01 F 0.02 F 0.0167 F None of the above
A single-phase half wave uncontrolled rectifier circuit is operating with a purely inductive load and a source voltage of 100 sin (277t) V. An ideal PMMC ammeter is connected in series with the inductive load reads 20 A. Calculate the distortion factor of the rectifier. Answer Choices: a. 0.866 b. 0.707 c. 0.577 d. 0.816
A charging circuit that will deliver constant DC current will be designed. The input of the circuit is 220V / 50Hz AC and its outputIt will be 5V / 2A DC.The circuit will consist of 3 parts:AC transformer will reduce the voltage on the inputii. AC rectifier circuit will convert low AC voltage to DCiii. Current source, this part will keep the current at the output constant.You determine the transformer drop rate in the first part. Its output is low voltage ACas the source and design the second and third parts accordingly.
Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V rmsh soHz} VL-DC =20V 0.01 F 0.02 F 0.0167 F None of the above
Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to c 20:5A L VI-DC20V 220V omsh T 0.01 F 0.02 F 0.0167 F None of the above euer
A 60 Hz sinusoidal voltage is applied to an SCR full-wave rectifier. If the DC output voltage is 74 V and the firing angle of the SCR is 60 degrees, the RMS voltage at the input would be: O A. 220 V O B.99 V O C. None of the other choices are correct OD. 110 V O E.256 V