
Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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A rectangular foundation 4 m x 6 m (Figure 1) transmits a stress of 100 kPa on the surface of a soil deposit. Plot the distribution of increases of vertical stresses with depth under points A, B, and C up to a depth of 20 m. At what depth is the increase in vertical stress below A less than 10% of the surface stress?
Can I get a detailed explanation to the solution of this question?
Including the finding of as and the graphs and finding the surface stress, load and increase in stress using the oz=4qsI method

Transcribed Image Text:ndation 4 m X 6 m (Figure Q1) transmits a stress
eposit. Plot the distribution of increases of vertical
3 and C up to a depth of 20 m. At what depth is the i
ss than 10% of the surface stress?
+2 m
A.
[Budhu M. Soil Mechanics & Foundo
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- 10.11 Refer to Figure 10.41. Due to application of line loads q, and q2, the vertical stress increase at point A is 42 kN/m². Determine the magnitude of q2. 91 = 292 kN/m 92 450 4.5 m 3 m- 3 m Figure 10.41 © Cengage Learning 2014arrow_forwardA circular foundation 2m in diameter is shown in the figure below. A normally consolidated clay layer 5m thick is located below the foundation. Determine the consolidation settlement of the clay. method 2:1 As one layer of clay of 5m thick: Divide the clay layer into (5) sub-layers each of 1m thick:Calculation of increase of stress below the center of each sub-layer Δσ ⃘(i): Weighted average pressure increase (Simpson's rule): "note in the picture solve the question but please solve in method 2:1"arrow_forwardFrom the given soil element, using the graphical method (Mohr's circle), determine the following: A) The values for the maximum and minimum principal stresses (0₁ and 3) B) The location of the pole C) The normal stress (a) and shear stress (ta) on the shear plane (dashed red line) D) In your own words and no more than a few sentences, explain the advantage of identifying the pole's location in a Mohr's circle graphical analysis. 40° 0 = 8 kPa Y -T₁ = 3 kPa yx T = -3 kPa xy o = 2 kPa Xarrow_forward
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