A poll conducted randomly in 2014 found that 52% of U.S. adult Twitter users get at least some news on Twitter. The standard error for this estimate was 2.4%, and a normal distribution may be used to model the sample proportion. Construct a 99% confidence interval for the fraction of U.S. adult Twitter users who get some news on Twitter, and interpret the confidence interval in context.

Q: what would be the 90% confidence interval of the true proportion of young adults who have received…

A: Given that sample size is n = 190 And the sample proportion is 70% = 0.7 At 90% confidence level,…

Q: In a random sample of 810 women employees, it is found that 81 would prefer working for a female…

A:

Q: In August 2004, Time magazine, reporting on a survey of men’s attitudes, noted that “Young men are…

A: It is given that out of 129 surveyed 18-24 year old men, 80 said they were comfortable talking about…

Q: A November 2018 CBS News Poll found that 35% of its sample planned to use online retailers for most…

A: Given that, A November 2018 CBS News Poll found that 35% of its sample planned to use online…

Q: When a survey asked subjects whether they would be willing to accept cuts in their standard of…

A: It is given that 362 out of 1,180 subjects respond yes.The sample proportion is 362/1,180 =…

Q: In a random sample of 500 people eating lunch at a cafeteria on various Fridays, it was found that…

A:

Q: A May 2000 Gallup poll found that 38% of a random sample of 1012 adults in the United States said…

A: (a)   Obtain the 96% confidence interval to estimate the true proportion of all U. S. adults who…

Q: In a recent Dew Research Poll, 500 U.S. adults were asked about their online versus in-store clothes…

A:

Q: Suppose in a recent poll of 1250 randomly selected Californians who took vacations, 132 of them…

A:

Q: A pew Poll conducted in 2013 surveyed a random sample of 2003 adult Americans, and 18% of them said…

A: The random variable X follows normal distribution. We have to construct 90% confidence interval.…

Q: In a random sample of 500 people eating lunch at a cafeteria on various Fridays, it was found that…

A: Given that Sample size n= 500  Favorable cases x=160 Sample proportion p^=x/n

Q: A Gallup Youth Survey in 2001 found that of 501 randomly selected teenagers in the U.S., 271 of them…

A: Given Total number of teenagers selected = 501Number of teenagers said who get along with their…

Q: Suppose that you will be taking a random sample from a population and that you intend to find a 95%…

A: Solution: The confidence interval for the population mean is calculated by using the following…

Q: What is the value of Z for this confidence interval?

A: Given,sample size(n)=14795no.of people who said yes=2219no.of people who said no =12576

Q: . If she wants to make a 95% confidence interval for the mean with the margin of error of 5 cm, at…

A: here from given information , σ = 17 cm MOE = 5cm here Z-critical for 95 % confidence level = 1.96…

Q: Find a 95% confidence interval for the proportion of renters.

A: It is given that  Favourable cases, X = 360 Sample size, n = 600 Confidence interval = 95%

Q: An automotive manufacturer wants to know the proportion of new car buyers who prefer foreign cars…

A:

Q: In a random sample of 170 customers, 90 ordered chicken sandwitches for lunch. Construct a 94%…

A: X = 90 N = 170

Q: kendall wants to estimate the percentage of vegetarians who are also vegan. She surveys 150…

A: The margin of error for the 95% confidence interval of population proportion is given as follows :…

Q: In a four-year psychedelic-mushroom experiment, 93 of the 300 subjects reported experiencing “strong…

A: Given information- We have given that 93 of the 300 subjects reported experiencing “strong or…

Q: . A researcher collects a sample of 24 measurements from a population and wishes to find a​ 99%…

A: The degrees of freedom is,

Q: In a 2009 Gallup Poll, 441 of 507 adults said it was “morally wrong” to clone humans. Assume Gallup…

A:

Q: Suppose that a 95% confidence interval for a population p = the population proportion of men who…

A:

Q: What value of z should be used to calculate a confidence interval with a 95% confidence level?

A: The z value which is used to calculate 95% confidence interval is defined as P(-zvalue < Z <…

Q: Identify the y-score for a 99% confidence interval if the sample size is 35.

A: We have to find critical value for given data..

Q: In a sample of 600 Ottawa families, it is found that 360 rent their dwellings while 240 own their…

A: It is given that sample size (n) is 360 and x is 240.

Q: in a random sample of 192 college students, 129 had part-time jobs. Find the margin of error for the…

A:

Q: In a certain high school, 7 out of 11 juniors said that they planned to go to the winter prom.…

A:

Q: In a sample of 900 people, 378 say they snooze the alarm more than once in the morning. Find a 95%…

A: Given,   The sample proportion is,

Q: In the previous example, you learned that the 95% confidence interval for the true proportion of all…

A: Calculate the point estimate and margin of error used to create this confidence interval.

Q: 3. In a sample of 300 people, 154 said that they watched news on television. Find the 90% confidence…

A: Given : Sample size of people (n) = 300 Let X : No. of people from sample  who said they watched…

Q: 1. A recent survey showed that from a sample of 500 packages delivered by a Postal Service, 480 were…

A: We have given that  Sample size n= 500 , favorable cases x=480 Sample proportion p^=x/n=…

Q: For many years businesses have struggled with the rising cost of health care. But recently, the…

A: Obtain the margin of error. The value of the margin of error is obtained below as follows: Use…

Q: A poll commissioned by the Center on Addiction and Substance Abuse at Columbia University found that…

A: Given that, X = 1340 N = 2000 98% confidence level

Q: A survey of 80 recent arcanum students showed that 46 were ready for summer break. Find the 95%…

A: Obtain the 95% confidence interval for the true proportion of students ready for summer break. The…

Q: A random sample of accountants were asked whether they double-check their calculations on a tax…

A: Here the sample proportion is given by, p^ Therefore α level confidence interval is given by, p^ -…

Q: find tc for a 95% confidence level when the sample size is 6.

A: level of significance, alpha = 0.05from standard normal table, two tailed t alpha/2 with n-1 = 6 d.f…

Q: A recent study of 750 internet users in Europe found that 35% of internet users were women. What is…

A: It is given that the study of 750 internet users in Europe found that 35% of internet users were…

Q: Identify the at-score for a 99% confidence interval if the sample size is 70.

A: givensample size(n)=70α=1-0.99=0.01

Q: A recent Gallup poll asked a random sample of 1010 Americans to respond to the statement, "If the…

A: Given,95% confidence interval for the proportion who would respond "Strongly agree" or "Agree" is…

Q: At one large college, 660 out of the 1500 students surveyed said they plan to take another science…

A: Given that,   x=660,n=1500 The sample proportion is, Critical values: By using the standard normal…

Q: A recent survey of 1,000 people found that 90% of Americans support background checks for purchasing…

A:

Q: A random sample of 180 men indicated that 50 were smokers, and a random sample of 150 women surveyed…

A: Given; p1=50180=0.28p2=39150=0.26Level of significance=0.02 Confidence interval is given by-…

Q: An airline transports over 10 000 passengers daily, and the airline is curious what proportion of…

A: Critical value: Using Excel formula "=NORM.S.INV(1-(0.1/2))", the z-value is obtained as 1.645.

Q: A random sample of married people were asked "would you remarry your spouse if you were given the…

A: Given information x = 127 N = 150

Q: A study of 150 randomly selected accidents that involved trips to the emergency room found that 36%…

A: Given 99% confidence level, significance level α=1-0.99=0.01

Q: It was found that in a sample of 90 teenage boys, 70% of them have received speeding tickets. What…

A: Given data ,n=90P=70%=0.7The z-value at 90% confidence is1.645=z∝12=1.645

Q: A statistics student wants to conduct a study to determine the proportion of workers in Cititon who…

A:

Q: In a survey of 900 adults, 240 said that they watched the World Cup final on television. Using these…

A: Given, The sample proportion is,

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.