Using the 99% level of confidence, what is the confidence interval for proportion of students attending home football games?

Q: A survey of 540 depressed shoppers found at 32% of them shop on impulse. What is the 99% confidence…

A: Given : Sample Size, n = 540 confidence level,c=0.99 Significance level, α…

Q: There are 3000 beads of various colors in a jar. In a sample of 125 beads, 40% were red. Calculate…

A:

Q: In a survey of 4026 ​adults, 708 oppose allowing transgender students to use the bathrooms of the…

A: Given:  n=4026 x=708

Q: results

A: Let X be the number of medical doctors that had a solo practice.  N : A sample size of medical…

Q: According to a Harris Interactive survey of 2401 adults conducted in April 2009, 25% of adults do…

A:

Q: survey​ asked, "How many tattoos do you currently have on your​ body?" Of the 1241 males​ surveyed,…

A: We have given that,n1=1241,x1=186,n2=1093,x2=129

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In poll,…

A:

Q: adults in a recent​ year, 742 made a New​ Year's resolution to eat healthier.   Construct​ 90% and​…

A: The value of z at a 90% confidence level is 1.645, which can be found by using the standard normal…

Q: In a survey of 2113 adults in a recent​ year, 741 made a New​ Year's resolution to eat healthier.…

A:

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: Suppose we take a survey of 200 students and ask how much they study per week. The result is an…

A: From the above data  We are given that the  95% confidence interval is (10, 10.5). The population…

Q: In a random sample of 170 customers, 90 ordered chicken sandwiches for lunch. Construct a 94%…

A:

Q: In a survey of 3985 ​adults, 711 oppose allowing transgender students to use the bathrooms of the…

A: Given, n=3985 x=711 To find a confidence interval for a population proportion.

Q: An accounting firm has 1200 clients. From a random sample of 120 clients, 110 indicated very high…

A: Given : An accounting firm has 1200 clients So,  Population size (N) = 1200 Sample size (n) = 120…

Q: A study done by researchers at a university concluded that 90​% of all student athletes in a country…

A:

Q: In a survey of 4008 ​adults, 728 oppose allowing transgender students to use the bathrooms of the…

A:

Q: In a survey of 4052 ​adults, 723 oppose allowing transgender students to use the bathrooms of the…

A: It is given that x = 723 and n= 4,052.

Q: The university is trying to estimate the percentage of students who failed more than two courses. In…

A: Step-by-step procedure to obtain the value of  using STATKEY:Choose Normal under Theoretical…

Q: A college admissions officer sampled 119 entering freshmen and found that 50 of them scored less…

A: Let X be the number  scored less than 525  n be the sample size  Given x=50, n=119, level of…

Q: Of 127 randomly selected adults, 31 were found to have high blood pressure. Construct a 95%…

A: Given that, Of 127 randomly selected adults, 31 were found to have high blood pressure.  X = 31 N =…

Q: When 302 college students are randomly selected and surveyed, it is found that 122 own a car. What…

A: E have to find point estimate with with confidance interval..

Q: In a survey of 1037 US adults ages 65 and over, 643 were concerned about getting the flu. A 99%…

A: Given,n=1037x=643p^=xnp^=6431037=0.6201-p^=1-0.620=0.380α=1-0.99=0.01α2=0.005Z0.005=2.58    (from…

Q: In a survey of 612 randomly selected female college students, 141 report that they had been sexually…

A: Given Information:n=612x=141c=95%=0.95

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 500…

A:

Q: in a survey of 2042 adults in a recent​ year, 715 made a New​ Year's resolution to eat healthier.…

A:

Q: a research poll institute asked respondents if they fet vulnerable to identify theft. in the poll,…

A: Given Data: n=1002 x=595 α=0.05   Calculating the sample proportion p⏜=xn=5951002=0.5938 As n is…

Q: n a survey of 4026 ​adults, 708 oppose allowing transgender students to use the bathrooms of the…

A:

Q: In your sample of 200 individuals, 10 people identified as bisexual. What is the true proportion of…

A:

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: Out of 300 people sampled, 171 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: A sample of 3048 randomly chosen people found that 341 of them were left-handed. Construct a 99%…

A: Sample proportion=p^=xn=3413048Critical value for 99% confidence interval is=z=2.576n=sample…

Q: aOf 500 random people surveyed, 72 were smokers. Find the 80% confidence interval for smokers.

A: It is given that, Out of 500 random people surveyed, 72 were smokers. So, the portion of the…

Q: a survey of 3409 adults, 1445 say they have started paying bills online in the last year.  Construct…

A: The confidence interval = 99%The faovarble cases [x] = 1445The sample size [n] = 3409

Q: In a survey of 1000 people, 850 said they would not to travel to Disney World this summer. Construct…

A: Given: n=1000 and x=850 Then,p^=xn=8501000=0.85

Q: andom sample of 1200 high school freshmen was taken and it was found that 559 of them were reading…

A: The population proportion (p) will be proportion of high school freshman who reads at or above their…

Q: n a survey of 3932 ​adults, 718 oppose allowing transgender students to use the bathrooms of the…

A:

Q: Commerce students were asked if they watch or listen to the state of the nation address (SONA), of…

A: Given: n= 220 ,x= 105 At 90.0 % confidence level , z score= 1.645 Need to find confidence interval…

Q: In a survey of 3983 ​adults, 747 oppose allowing transgender students to use the bathrooms of the…

A:

Q: A survey found that 39 of 66 people who don't drink coffee often have trouble sleeping and 44 of 88…

A: Solution: Let X1 be the number of noncoffee drinkers who have trouble sleeping, n1 be the sample…

Q: 82 adults selected randomly from one town, 66 have health insurance. Find a 90% confidence interval…

A:

Q: Identify the y-score for a 99% confidence interval if the sample size is 35.

A: We have to find critical value for given data..

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.