expected frequency

A population of 1000 beetles has 600 individuals that have genotype QQ, 100 individuals that have genotype Qq, and 300 individuals that have genotype qq.   a) Calculate f(Q) and f(q) for this population. Show your work and don’t assume HWE.       b) Calculate f(QQ), f(Qq), and f(qq) for this population. Show your work and don’t assume HWE.       c) Calculate the expected genotype frequencies if the population is in Hardy-Weinberg equilibrium. Show your work.       d) Does this population appear to be at Hardy-Weinberg equilibrium? Why or why not? (Although answering this question rigorously would require a statistical test, you don’t need to do that here.).

The two-tailed p-value associated with this test is 0.860. Should the null hypothesis be rejected? Is there sufficient evidence to suggest that there is a statistically significant difference between the two means in question? If we now wanted to know whether there was a difference in weight between those with a low NYHA class (1 and 2) and those with a high NYHA class (3 and 4), what p-value would you report?

Pretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem.  So your hypothesis is that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations).  If you carry out a chisquare goodness of fit test and calculate a total chisquare value of 0.03 with 1 degree of freedom (see table), what does this mean? (select all true statements)a) The data do NOT fit the hypothesized distribution.b) The data do fit the hypothesized distribution well enough, so we accept the hypothesis at this time (i.e. we cannot reject the hypothesis). c) The probability that the data came from a population in Hardy-Weinberg equilibrium is too small, so we reject the hypothesis.d) The probability that the data came from a population in Hardy-Weinberg equilibrium is too big, so we reject the hypothesis.e) The data support Hardy-Weinberg expectations – there is no…

Consider an autosomal locus with alleles A and a. If the the allele frequencies are as follows Freq(A) = 0.4, Freq(a) = 0.6. , then what is the predicted frequency of heterozygous Aa individuals, assuming the population is in Hardy-Weinberg equilibrium? Freq(Aa) = ? Enter a number between 0 and 1, inclusive, for example 0.33

In a population with two alleles at the R locus (R and r), the frequency of the genotype rr is 0.10. Assuming that the R locus is at Hardy-Weinberg equilibrium in this population, what is the frequency of heterozygotes (Rr)? Round and report your answer to the second decimal place (0.00).

The UNF penguin lab decided to study the elusive polka dot penguin of Patagonia. They trapped a majority of the population using gummy worms as bait and collected the following information. Observed Genotype Frequencies (not in HWE) AA: 0.464 Aa: 0.427 aa: 0.109 If this population was in Hardy-Weinberg Equilibrium, what would be the expected genotype frequency for the heterozygotes? Retain 3 decimal places.