A particle with a mass of 5.00 x 1016 kg and a charge of 21.0 nC starts from rest, is accelerated through a potential difference AV, and is fired from a small source in a region containing a uniform, constant magnetic fiel of magnitude 0.600 T. The particle's velocity is perpendicular to the magnetic field lines. The circular orbit of the particle as it returns to the location of the source encloses a magnetic flux of 15.0 uwb. (a) Calculate the particle's speed. m/s (b) Calculate the potential difference through which the particle was accelerated inside the source.

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A calcium ion (Ca2+) has mass m = 6.56 × 10−26 kg and istraveling horizontally with a speed of 75 km/s. It enters asquare-shaped region of space that lies in the x-y plane andcontains a uniform magnetic field B = 5.0 mT that points inthe negative z direction. The ion enters this region at themidpoint of one of the square’s sides, with its velocity vectorperpendicular to that side. It exits this region at the midpointof one of the adjacent sides (not the side opposite from whereit entered), with its velocity vector perpendicular to that side.How much arc length S does the ion cover while inside thefield region?

Doubly-ionized particles with an atomic mass of 59.4 u are moving due N at a speed of 7.78 x 105 m/s when they enter a uniform magnetic field of strength, B = 35.5 mT. The ions, which are moving perpendicular to the field, follow a circular path of radius, r, and travel north a distance, h = 2.02 m, before leaving the field at an angle, 8, as shown in the figure. (a) What is the radius of the ions' circular path? r = 6.793 m (b) At what angle do the ions leave the field? 0 = 73.44 x h 0 2

A proton has a velocity of 1.1X10^2 m/s î +1.8X10^2 m/s ĵ and is located in the z=0 plane at x=3.4m, y=3.6m at some time t=T. Find the magnetic field in the z=0 plane at the following at x=1.9m, y=1.9m.

A magnetic dipole with a dipole moment of magnitude 0.0306 J/T is released from rest in a uniform magnetic field of magnitude 57.6 mT. The rotation of the dipole due to the magnetic force on it is unimpeded. When the dipole rotates through the orientation where its dipole moment is aligned with the magnetic field, its kinetic energy is 0.573 mJ. (a) What is the initial angle between the dipole moment and the magnetic field? (b) What is the angle when the dipole is next (momentarily) at rest?

An electron initially at rest is accelerated through a potential difference of 3 kV in the positive x- direction. It enters a region where a uniform magnetic field of 5.0-mT is in a positive y-direction (perpendicular to the velocity of the electron). Calculate the radius of the path this electron will follow in the magnetic field. (e = 1.60 × 10-19 c, m electron = 9.11 × 10¯31 kg)

A 1.00 C charge enters a uniform magnetic field. The magnetic field vector has the following components:  1.00 T in the x-direction, 2.00 T in the y-direction, and 3.00 T in the z-direction.  The particle enters the magnetic field with a constant velocity whose components are as follows: 4.00 m/s in the x-direction, 5.00 m/s in the y-direction, and 6.00 m/s in the z-direction. - What are the components of the magnetic force in the particle? (Fx, Fy, and Fz) -  What is the magnitude of the magnetic force?

A uniform magnetic field points vertically upward; its magnitude is 0.520 T. An electron with kinetic energy 6.50 × 10−18 J is moving horizontally eastward in this field. What is the magnetic force acting on it? Answer in units of "N north"

A proton moves in a circular motion perpendicular to a uniform magnetic field of 0.75 T. Find the time for the proton to make one complete circular orbit.