A mediocre hash map stores each value in a single container (that is, they are all in the same LinkedList). Hash maps work.

Because of the shoddy way in which the map was built, all of the hash map's contents are contained in a single LinkedList. The hash map's utility is reduced as a consequence.

JAVA please Given main() in the ShoppingList class, define an insertAtEnd() method in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node. Ex. if the input is: 4 Kale Lettuce Carrots Peanuts where 4 is the number of items to be inserted; Kale, Lettuce, Carrots, Peanuts are the names of the items to be added at the end of the list. The output is: Kale Lettuce Carrots Peanuts Code provided in the assignment ItemNode.java:

All of the information for our hash map is kept in a single container called a LinkedList because of the way the map was built. Because of this, a hash map's utility is reduced.

Due to the way the map was constructed, all of the data for the hash is stored in a single container, a LinkedList. This decreases a hash map's usefulness.

Given main.py and a PersonNode class, complete the PersonList class by writing find_first() and find_last() methods at the end of the PersonList.py file. The find_first() method should find the first occurrence of an age value in the linked list and return the corresponding node. Similarly, the find_last() method should find the last occurrence of the age value in the linked list and return the corresponding node. For both methods, if the age value is not found, None should be returned. The program will replace the name value of each found node with a new name. Ex. If the input is: Alex 23 Tom 41 Michelle 34 Vicky 23 -1 23 Connor 34 Michela   main.py(can not edit) from PersonNode import PersonNodefrom PersonList import PersonList if __name__ == "__main__":    person_list = PersonList()        # Read input lines until encountering '-1'    input_line = input()    while input_line != '-1':        split_input = input_line.split(' ')        name = split_input[0]        age =…

Java Built-in Comparator interface, Java Built-in  Collections class : A simple case of how to sort LinkedList using Comparator.  Please use Java Built-in LinkedList class.  (https://docs.oracle.com/javase/8/docs/api/allclasses-noframe.html Please make a summary for Java built-in Comparator interface & Collections class (especially sort(list, c) methods in Collections class).   Define a Person class which has name and age. Also define an ageComparator class which implements Comparator interface to compare the age of people. Please create 5 instances from Person class and put them into a LinkedList at any order.   Sort them by their ages in ascending order, and print them. You can put the pseudo code here (or you can write in Java code and submit the Java file with its output).         )

True or false: a) We can use memory maps with LinkedLists. b) If all of the JUnit tests pass, the program is guaranteed to always work.

We utilise a subpar hash map that stores all data in one LinkedList. Hash maps work well.

Our hash map's data is stored in a LinkedList due to its design. A hash map's usefulness decreases.