A mass m = 0.4 kg is attached to a vertical hanging spring, which obeys Hooke's Law. After hanging the weight the spring is stretched from its equilibrium position by Ayo = 0.1 m. The mass is then extended an additional Ay released from rest. The period of this system is = 0.1 m downward and bohog edi gaiureser (a) T = 0.010 s

Inquiry into Physics
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Chapter2: Newton's Laws
Section: Chapter Questions
Problem 28P: . A mass of 0.75 kg is attached to a relaxed spring with k = 2.5 N/m. The mass rests on a...
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2. A mass m = 0.4 kg is attached to a vertical hanging spring, which obeys Hooke's
Law. After hanging the weight the spring is stretched from its equilibrium position by
Ayo = 0.1 m. The mass is then extended an additional Ay = 0.1 m downward and
released from rest. The period of this system is
yalw.Jiee od diiw obiln sdi lo edi
borog
ranem od
(a) T = 0.010 s
(b) T = 0.063 s
(c) T = 0.100 s
e cHontp po me m to bSLIO
ofla llema oo comonad ob
lo noido odT (d)
(d) T = 0.628 s
wgola sdt goa ot odw
Transcribed Image Text:2. A mass m = 0.4 kg is attached to a vertical hanging spring, which obeys Hooke's Law. After hanging the weight the spring is stretched from its equilibrium position by Ayo = 0.1 m. The mass is then extended an additional Ay = 0.1 m downward and released from rest. The period of this system is yalw.Jiee od diiw obiln sdi lo edi borog ranem od (a) T = 0.010 s (b) T = 0.063 s (c) T = 0.100 s e cHontp po me m to bSLIO ofla llema oo comonad ob lo noido odT (d) (d) T = 0.628 s wgola sdt goa ot odw
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