A 0.75-kg block oscillates on the end of a spring with a spring constant of 100 N/m. The oscillation is started by elongating the spring 10 cm from its equilibrium position, then giving the block a speed of 2 m/s. What is the amplitude of oscillation? O A = 0.4 m O A = 0.1 m A = 0.5 m O A = 0.2 m O A = 0.3 m

Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
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Chapter12: Oscillatory Motion
Section: Chapter Questions
Problem 17P: A block of unknown mass is attached to a spring with a spring constant of 6.50 N/m and undergoes...
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A 0.75-kg block oscillates on the end of a
spring with a spring constant of 100 N/m.
The oscillation is started by elongating the
spring 10 cm from its equilibrium position,
then giving the block a speed of 2 m/s.
What is the amplitude of oscillation?
O A = 0.4 m
O A = 0.1 m
O A = 0.5 m
O A = 0.2 m
O A = 0.3 m
Transcribed Image Text:A 0.75-kg block oscillates on the end of a spring with a spring constant of 100 N/m. The oscillation is started by elongating the spring 10 cm from its equilibrium position, then giving the block a speed of 2 m/s. What is the amplitude of oscillation? O A = 0.4 m O A = 0.1 m O A = 0.5 m O A = 0.2 m O A = 0.3 m
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