A long solid bar (k=30 W/m.K) of rectangular cross section is exposed to a constant heat flux on one surface and is subjected to convection on the opposite surface. The other two surfaces are maintained at constant temperatures as shown. Using a uniform mesh size Ar=Ay=1 cm, 6.1 express the finite difference equations for nodes 1, 2 and 3, and 6.2 solve for the nodal temperatures. 100 °C q=5,000 W/m² 300 °C Ax 3 ду h-150 W/m²K Too = 25 °C

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Chapter4: Numerical Analysis Of Heat Conduction
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Problem 4.46P
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A long solid bar (k=30 W/m.K) of rectangular cross section is exposed to a constant heat flux on
one surface and is subjected to convection on the opposite surface. The other two surfaces are
maintained at constant temperatures as shown. Using a uniform mesh size Ax=Ay=1 cm,
6.1 express the finite difference equations for nodes 1, 2 and 3, and
6.2 solve for the nodal temperatures.
100 °C
q=5,000 W/m²
300 °C
ΔΧ
3
ду
h = 150 W/m²K
Too = 25 °C
Transcribed Image Text:A long solid bar (k=30 W/m.K) of rectangular cross section is exposed to a constant heat flux on one surface and is subjected to convection on the opposite surface. The other two surfaces are maintained at constant temperatures as shown. Using a uniform mesh size Ax=Ay=1 cm, 6.1 express the finite difference equations for nodes 1, 2 and 3, and 6.2 solve for the nodal temperatures. 100 °C q=5,000 W/m² 300 °C ΔΧ 3 ду h = 150 W/m²K Too = 25 °C
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