A jogger with mass m = 55 kg uses energy at a rate of P = 745 W when she jogs on horizontal ground at a constant speed of s = 4.6 m/s. The efficiency of her “human engine” however, is e = 0.37. (In other words, the power used for locomotion is e = 0.37 times the total power.)  a. Write an expression for the rate of energy expenditure when she jogs at the same constant speed up a slope of φ = 6.21 degrees. Assume whatever frictional or drag forces are the same in each case. Your answer should be in terms of the symbols given in the problem statement and g (9.80 m/s2).  b. What is the rate of energy expenditure when she jogs up the slope, in watts?

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Chapter7: Work, Energy, And Energy Resources
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A jogger with mass m = 55 kg uses energy at a rate of P = 745 W when she jogs on horizontal ground at a constant speed of s = 4.6 m/s. The efficiency of her “human engine” however, is e = 0.37. (In other words, the power used for locomotion is e = 0.37 times the total power.) 

a. Write an expression for the rate of energy expenditure when she jogs at the same constant speed up a slope of φ = 6.21 degrees. Assume whatever frictional or drag forces are the same in each case. Your answer should be in terms of the symbols given in the problem statement and g (9.80 m/s2). 

b. What is the rate of energy expenditure when she jogs up the slope, in watts? 

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