A hospital wishes to try a new antibiotic scrub before surgery to see whether it can lower the rate of infections of surgical sites. The old rate of infection is 4%. Out of a random sample of 1000 patients, we find an infection rate of 3.6% using the new scrub. We run a z-test and find z-stat= -0.6454 and we get a p-value of 0.2593. The null hypothesis is that... p=0.04 p>0.04 p<0.04 p=0.036

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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A hospital wishes to try a new antibiotic scrub before surgery to see whether it can lower the rate of
infections of surgical sites. The old rate of infection is 4%. Out of a random sample of 1000 patients,
we find an infection rate of 3.6% using the new scrub. We run a z-test and find z-stat= -0.6454 and we
get a p-value of 0.2593. Which of the following is the correct interpretation of the p-value?
The probability the infection rate is truly 4%, given our extreme sample value of 3.6% , is 25.93%
The probability our z-stat is -0.6454 is 3.6%.
The new infection rate is .2593%
Given our sample, the probability the infection is 3.6% is .2593
Transcribed Image Text:A hospital wishes to try a new antibiotic scrub before surgery to see whether it can lower the rate of infections of surgical sites. The old rate of infection is 4%. Out of a random sample of 1000 patients, we find an infection rate of 3.6% using the new scrub. We run a z-test and find z-stat= -0.6454 and we get a p-value of 0.2593. Which of the following is the correct interpretation of the p-value? The probability the infection rate is truly 4%, given our extreme sample value of 3.6% , is 25.93% The probability our z-stat is -0.6454 is 3.6%. The new infection rate is .2593% Given our sample, the probability the infection is 3.6% is .2593
A hospital wishes to try a new antibiotic scrub before surgery to see whether it can lower the rate of
infections of surgical sites. The old rate of infection is 4%. Out of a random sample of 1000 patients,
we find an infection rate of 3.6% using the new scrub. We run a z-test and find z-stat= -0.6454 and we
get a p-value of 0.2593. The null hypothesis is that..
p=0.04
p>0.04
p<0.04
p=0.036
Transcribed Image Text:A hospital wishes to try a new antibiotic scrub before surgery to see whether it can lower the rate of infections of surgical sites. The old rate of infection is 4%. Out of a random sample of 1000 patients, we find an infection rate of 3.6% using the new scrub. We run a z-test and find z-stat= -0.6454 and we get a p-value of 0.2593. The null hypothesis is that.. p=0.04 p>0.04 p<0.04 p=0.036
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