A hospital wishes to try a new antibiotic scrub before surgery to see whether it can lower the rate of infections of surgical sites. The old rate of infection is 4%. Out of a random sample of 1000 patients, we find an infection rate of 3.6% using the new scrub. We run a z-test and find z-stat= -0.6454 and we get a p-value of 0.2593. The null hypothesis is that... p=0.04 p>0.04 p<0.04 p=0.036

A random sample of n = 25 individuals is selected from a population with µ = 20, and a treatment is administered to each individual in the sample. After the treatment, the sample mean is found to be M = 22.2, with SS =384. Based on the sample data, does the treatment have a significant effect? Use a two-tailed test with α = .05. Write the hypothesis test out on a homework worksheet so that you can check your work. Then answer the question below: What is the critical value?

Apple, Inc. reported that "0.5% (0.005) of participants received irregular pulse notifications indicative of possible AFib" which is a dangerous heart condition that needs an immediate trip to the emergency room. To improve benefits of pulse notifications, it is important to identify the percentage of people receiving false notifications. A cardiologist is concerned that the percentage of people who actually have these types of irregular heartbeats is not accurate. The doctor randomly selected a simple random sample of 2315 adults who own Apple watches and asked if they have received one of these irregular heartbeat notifications. Nine of the respondents reported receiving such a notification. Does this evidence support the cardiologists claim that the percentage of people who receive notifications of irregular heartbeats is not 0.5% (0.005)? Can the conditions for the 1-proportion Z- test be met? No, normality cannot be met. Yes, all conditions are met. No, some part of the binomial…

The recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day. An article reports the following summary data on intake for a sample of males age 65-74 years: n = 113, x = 12.4, and s = 6.63. Does this data indicate that average daily zinc intake in the population of all males age 65-74 falls below the recommended allowance? (Use a = 0.05.) State the appropriate null and alternative hypotheses. O Ho: H = 15 H: u > 15 O Ho: H = 15 H: u < 15 Ο H: μ15 H:us 15 Ο Η: μ- 15 H: u = 15 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = p-value = State the conclusion in the problem context. O Reject the null hypothesis. There is sufficient evidence that average daily zinc intake falls below 15 mg/day. O Do not reject the null hypothesis. There is sufficient evidence that average daily zinc intake falls below 15 mg/day. O Do not reject the null hypothesis. There…