A four-bar mechanism is working on horizontal plane. The second link length is 0,4 m and makes an angle of 0=25 degrees with the vertical line as shown in figure. Find the torque (T) in Nm must be applied to link 2 to keep the mechanism in equilibrium against a F=132 N force acting at E on the link 3 downward (along negative y- axis) direction. Allowable tolerance for your answer of this question is relatively 3 percent. So, work precisely and clear while solving it. Do not enter any UNIT. (If the direction of the torque is CCW, just enter the value of it without any sign. If it has CW direction, enter "-" sign "negative sign" before the value such as "- 12,12".)

Mechanics of Materials (MindTap Course List)
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ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter3: Torsion
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A four-bar mechanism is working on horizontal plane. The second link length is 0,4 m and makes an angle of 0=25 degrees with the vertical line as shown in figure.
Find the torque (T) in Nm must be applied to link 2 to keep the mechanism in equilibrium against a F=132 N force acting at E on the link 3 downward (along negative y-
axis) direction.
Allowable tolerance for your answer of this question is relatively 3 percent. So, work precisely and clear while solving it. Do not enter any UNIT.
(If the direction of the torque is CCW, just enter the value of it without any sign. If it has CW direction, enter "-" sign "negative sign" before the value such as "- 12,12".)
AB=CD
AD=BC=0.7 m
BE=EC
В
TF
Transcribed Image Text:A four-bar mechanism is working on horizontal plane. The second link length is 0,4 m and makes an angle of 0=25 degrees with the vertical line as shown in figure. Find the torque (T) in Nm must be applied to link 2 to keep the mechanism in equilibrium against a F=132 N force acting at E on the link 3 downward (along negative y- axis) direction. Allowable tolerance for your answer of this question is relatively 3 percent. So, work precisely and clear while solving it. Do not enter any UNIT. (If the direction of the torque is CCW, just enter the value of it without any sign. If it has CW direction, enter "-" sign "negative sign" before the value such as "- 12,12".) AB=CD AD=BC=0.7 m BE=EC В TF
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