A countershaft carrying two V-belt pulleys is shown in the figure. Pulley A receives power from a motor through a belt with the belt tensions shown. The power is transmitted through the shaft and delivered to the belt on pulley B. Assume the belt tension on the loose side at Bis 15 percent of the tension on the tight side. Given: B(dg) = 7 in, TA) = 560 lb, and TA2) = 93.333 Ib. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.

For two existing torques, what third force at a given distance from the pivot will balance them? Imagine a meter stick set up as in the figure. It hangs from a central bracket, and two hanging masses can hang from it from each of their brackets. At a third location, a force probe can either pull up or pull down on the stick, depending on what is needed to balance the stick. The mass of the meter stick is 120 g. sketch the situation (drawing r1, r2, r3, F1, F2, and F3) and determine the magnitude (value) and direction (+ or -) of each torque. Don't include the mass of a bracket that would hold the hanging mass in place; assume the mass listed is the entire mass hanging at that point. For each trial, use the principle of equilibrium (where the sum of torques is zero) to calculate the third, unknown force acting at x3

For two existing torques, what third force at a given distance from the pivot will balance them? Imagine a meter stick set up as in the figure. It hangs from a central bracket, and two hanging masses can hang from it from each of their brackets. At a third location, a force probe can either pull up or pull down on the stick, depending on what is needed to balance the stick. The mass of the meter stick is 120 g. sketch the situation (drawing r1, r2, r3, F1, F2, and F3) and determine the magnitude (value) and direction (+ or -) of each torque. Don't include the mass of a bracket that would hold the hanging mass in place; assume the mass listed is the entire mass hanging at that point. For each trial, use the principle of equilibrium (where the sum of torques is zero) to calculate the third, unknown force acting at x3

For two existing torques, what third force at a given distance from the pivot will balance them? Imagine a meter stick set up as in the figure. It hangs from a central bracket, and two hanging masses can hang from it from each of their brackets. At a third location, a force probe can either pull up or pull down on the stick, depending on what is needed to balance the stick. The mass of the meter stick is 120 g. sketch the situation (drawing r1, r2, r3, F1, F2, and F3) and determine the magnitude (value) and direction (+ or -) of each torque. Don't include the mass of a bracket that would hold the hanging mass in place; assume the mass listed is the entire mass hanging at that point. For each trial, use the principle of equilibrium (where the sum of torques is zero) to calculate the third, unknown force acting at x3

Assume if the shear stress in steel exceeds about 4.00 x 108 N/m² the steel ruptures. .(a)..Determine the shearing force necessary to shear a steel bolt 1.05 cm in diameter. Enter a number. differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. N (b) Determine the shearing force necessary to punch a 2.00-cm-diameter hole in a steel plate 0.410 cm thick. N

A crank shaft is operated as shown in the figure. A load F1 = 9.73 N is applied and the operator %3D dz applies a load P to counter. The system is in equilibrium and all of the bearings are perfectly dz aligned such that they do not produce moments on the rotating crank. The geometry is given by, w = 7.31 [m), dl = 9.69 m], d2 = 7.57 m). 6.14 (m), d5 = 3.7 (m), %3D d1 d3 = 9.87 (m), d4 %3D F2 and h1 4.4 (m), find the following: %3D F1 Part 1. Express the reaction forces exerted on the bar by the journal bearing at point B. Use the coordinate system shown in the diagram 10 5% 100% Submit [N] Part 2. Express the reaction forces exerted on the bar by the journal bearing at Point A. Use the coordinate system shown in the diagram. 5% 100% 10 Submit [N]

Determination of vertical displacement of Mid-Term Project pipe assembly Find the vertical displacement at position C in the figure. 800 mm Pipe inner diameter: 40 mm, Pipe outer diameter: 60 mm Material: A-36 Steel 600 N B. -By the force 600N, the AB part of the pipe is subjected to bending and torsional loads. BC part is subjected to bending load. -The energy equation by this load is as follows. Energy equation by torsional load: 400 mm T²dx (U), = 2GJ Problem: Energy equation by bending load a) First, draw a free body diagram and the AB part Of the bending/torsional load of the BC and Derive the bending load equation. So M²dx (U) = 2EI By applying it to the high energy formula, Save energy and make it the same as external energy Release to find the vertical displacement. -The sum of the internal energy of 2 energy is as follows. U=U: +Ub b) Creo modeling and structural analysis -Due to energy conservation, the sum of the internal energy U is the external due to the load 600 NGet the…

Theory of machines

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