A drug company claims that their products’ contaminations never vary by more than 2%. Sample of 5 specimens were tested and the percentages of the purities are recorded as Observation no. 1 2 3 4 5 Percentages (%) 98.8 97.2 98.9 97.7 97.9 a. Do the sample data have enough proof to oppose the manufacturer's claim? (HINT: take the range of 2% equal 46.) b. Find a 90% confidence interval for o?.

To reduce bias, one should a. get a better instrument b. take the average of several measurements c. use rate rather than a count d. unbias your results

(3-B is needed to answer it I am only asking for question 4.) 3) You go out and collect the following estimates of earthworms / acre:54,276 57,378 51,108 66,190 66,232 59,018 57,159These data yield the following: ̄y = 59,765.86, and s = 5,689.606a) Construct a 90% CI for these data.b) Construct a 99% CI for these data.c) Darwin once estimated that an acre of soil had about 50,000 worms in it. Is his estimateconsistent with the data above? (Historical note: His estimate was considered way too high inhis day). 4) Consider the results of 3(b). Notice that all the data fit within the 99% confidence interval. Is thisusually the case (in other words, will a 99% CI contain most of the observations)?Caution: a lot of people get this wrong! Here's a hint: suppose you had measured the worms in6000 acres (instead of just 7). What happens to the confidence interval? If you're not sure,substitute 6,000 for 7 in your calculation for (b) to see what happens.

This data was collected from the members of our class. I have tried to remove anything that would identify an individual. 1. What is the scale of each variable? 2. Construct a frequency table and chart showing the distribution across gender in this class. 3. Construct a cross tabulation with Gender in one direction and Height in the other direction. Group the height category into 5 groups. 4. Is there a difference in the age distribution across gender? 5. Give a summary of our class based on this data about our class.   Gender Height Year Born Male 76 1994 Male 72 1983 Female 65 1997 Male 68 1966 Female 67 1997 Male 70 1996 Male 71 1996 Male 73 1996 Male 72 1995 Male 71 1998 Male 73 1993 Female 66 1980 Female 62 1998 Male 76 1984 Female 70 1985 Female 62 1992 Female 62 1992 Male 73 1996 Female 68 1987 Male 60 1971 Female 60 1971 Male 60 1971 Male 74 1970 Male 77 1998 Male 77 1998 Male 68 1990 Female 64 1996 Male 80 1997 Male…

A magazine used the summated rating of 10 restaurants to predict the cost of a restaurant meal. For that data, SSR = 131,437.56 and SST=140,767.27. Complete parts (a) through (c). a. Determine the coefficient of determination, , and interpret its meaning. 2= (Round to four decimal places as needed.)

11. The variance for the weight of a breed of cattle is 256 lb2. The mean is 453 lb. How heavy would the animal have to be to be in the top 16% of the herd? Select one:a. 719 lbs.b. 479 lbs.c. 511 lbs.d. 463 lbs.

Statistics Question

Betty, an employee of Shining Sun Daycare Centerread an article in Healthy Child Magazine sayingthat the average 3-year-old child is 37 in. tall.Betty works with 10 3-year-olds at Shining Sun,so later that week, she measured the height ofeach child who had just turned or was about toturn 3 years old. Here are the descriptive statisticsfor the sample: M = 35, s = 3.1. State the nondirectional hypothesis.2. Determine the critical t for a = .05.3. Calculate t. Show your calculations.4. Is the height of 3-year-olds in Shining SunDaycare Center significantly different fromthe height given in the magazine?

9a. For binomially distributed data set, approximately what proportion would be below the mean and also within one standard deviation? 16.5%,25%,33%,50%,66%

Solve the problem. Find the standardized test statistic t for a sample with n = 15, x = 8.7, s = 0.8, and a = 0.05 if Ho: Hs 8.4. Round your answer to three decimal places. a. 1.452 b. 1.631 c. 1.728 d. 1.312