A data set lists weights (lb) of plastic discarded by households. The highest weight is 5.31 lb, the mean of all of the weights is x = 2.225 lb, and the standard deviation of the weights is s= 1.822 lb. a. What is the difference between the weight of 5.31 lb and the mean of the weights? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the weight of 5.31 lb to a z score. d. If we consider weights that convert to z scores between -2 and 2 to be neither significantly low nor significantly high, is the weight of 5.31 lb significant? a. The difference is lb. (Type an integer or a decimal. Do not round.) b. The difference is standard deviations. (Round to two decimal places as needed.) c. The z score is z= (Round to two decimal places as needed.) d. The highest weight is ▼

An agent for a residential real estate company in a suburb located outside a major city has the business objective of developing more accurate estimates of the monthly rental cost for apartments. Toward the g the agent would like to use the size of an apartment, as defined by square footage to predict the monthly rental cost. The agent selects a sample of 8 one-bedroom apartments and the data are shown. Comple parts (a) through (f). a. Construct a scatter plot. Choose the correct graph below. O A. 2,000 ★Rent ($) → 2,000 Size (sq ft) Q O B. ★Rent ($) 2,000+ to Monthly Rent ($) Size (Square Feet) 0 S 1.₂ 2,000 Size (Sq ft) Q Q □ b. Use the least-squares method to determine the regression coefficients bo and b₁. 900 1,600 825 1,450 1,900 975 1,825 1,300 900 1,200 1,050 1,200 1,900 700 1,350 1,100 bo = (Round to one decimal place as needed.) b₁ = (Round to one decimal place as needed.) c. Interpret the meaning of bo and b₁ in this problem. Choose the correct answer below. (---) O C. 2,000…

The heights of Crepe Myrtle saplings at a local nursery are measured and the data recorded. The data is then plotted and the distribution is found to be bell-shaped. The mean of the set is 67 inches and the standard deviation is 3 inches. A graph of the situation is shown below: 58 61 64 67 70 73 76 a) What percentage of the saplings is more than 70 inches tall? b) What percentage of the saplings is between 61 and 73 inches tall?

Assume the selling prices of homes in a particular community follow a normal distribution with a mean of $263,100 and a standard deviation of $43,200. Complete parts a through c. a. Determine the range of selling prices in this community that includes one standard deviation around the mean. The range is from $ to $ (Type integers or decimals. Use ascending order.) b. Determine the range of selling prices in this community that includes two standard deviations around the mean. The range is from $ to $ (Type integers or decimals. Use ascending order.) c. Determine the range of selling prices in this community that includes three standard deviations around the mean. The range is from $ to $1. (Type integers or decimals. Use ascending order.)

Please answer a and b

4. From the data given below, find the number of items. Er = 90 r = 0.5 Exy = 120 Oy = 8 (where x and y are deviations from arithmetic average).

A scale is known to be "low-calibrated" in that it measures an aluminum bar to be 4 grams lower than the actual weight.   If ????μold is the mean of all possible measurements of the bar using the old calibration,   and  ????μnew is the mean of all possible measurements of the bar using a re-calibrated scale.  It is desired that     ????−????=4μnew−μold=4.     Consider the test           ?0:????−????=4H0:μnew−μold=4   vs.  ?0:????−????≠4H0:μnew−μold≠4        Sample after calibration:     mean  is  95.8   ,     SD  is   4.9     and sample size is 10 Sample before calibration:       mean  is  89.352   ,     SD  is   4.2      and sample size is 62 We do not know population standard deviations.   What is the p-value?       (Hint:  best to use software, or else the Desmos Calculator for the 2 sample T and Z test)

A population of N=5 scores has a mean of μ=8. If one score with a value of X=4 is removed from the population, what is the value for the new mean? a. μ=9 b. μ=10 c. μ=8 d. μ=7

The average height of 1,000 children is 150cm with a standard deviation of 10cm. How many children stand between 155cm and 150cm ? A. Find the raw score for z= -1,-2,-3,+1,+2,+3 B. Sketch the graph C. What z score corresponds to 50? D. What z score corresponds to 60? E. Find the total area . F. Multiply the total area by 1000. G. Make a conclusion.

Suppose that 50 measurements were taken and the mean was calculated to be 4.55. Assume next that one of the data items was 19.4This was assumed to be an outlier as was discarded. What would be the mean of the remaining 49 numbers? I